我想遍历一个文件列表。这个列表是一个find命令的结果，所以我想出了:
getlist() {
for f in $(find . -iname "foo*")
do
echo "File found: $f"
# do something useful
done
}
这很好，除非文件名称中有空格:
$ ls
foo_bar_baz.txt
foo bar baz.txt
$ getlist
File found: foo_bar_baz.txt
File found: foo
File found: bar
File found: baz.txt
我能做些什么来避免空格分割?
当前回答
我真的很喜欢for循环和数组迭代，所以我想我会把这个答案添加到混合…
我也喜欢marchelbling愚蠢的文件示例。：）
$ mkdir test
$ cd test
$ touch "stupid file1"
$ touch "stupid file2"
$ touch "stupid file 3"
在test目录中:
readarray -t arr <<< "`ls -A1`"
这将每个文件列表行添加到名为arr的bash数组中，并删除任何尾随换行符。
假设我们想给这些文件取一个更好的名字……
for i in ${!arr[@]}
do
newname=`echo "${arr[$i]}" | sed 's/stupid/smarter/; s/ */_/g'`;
mv "${arr[$i]}" "$newname"
done
$ {!arr[@]}扩展到0 1 2，因此"${arr[$i]}"是数组的第i个元素。变量周围的引号对于保留空格很重要。
结果是三个重命名的文件:
$ ls -1
smarter_file1
smarter_file2
smarter_file_3
其他回答
另一个解决工作的方法是……
目标是:
递归地选择/过滤目录中的文件名 处理每个名称(路径…中的任意空格)
#!/bin/bash -e
## @Trick in order handle File with space in their path...
OLD_IFS=${IFS}
IFS=$'\n'
files=($(find ${INPUT_DIR} -type f -name "*.md"))
for filename in ${files[*]}
do
# do your stuff
# ....
done
IFS=${OLD_IFS}
find . -name "fo*" -print0 | xargs -0 ls -l
见xargs先生。
你可以用基于行的迭代替换基于单词的迭代:
find . -iname "foo*" | while read f
do
# ... loop body
done
好的，这是我在Stack Overflow上的第一篇文章!
Though my problems with this have always been in csh not bash the solution I present will, I'm sure, work in both. The issue is with the shell's interpretation of the "ls" returns. We can remove "ls" from the problem by simply using the shell expansion of the * wildcard - but this gives a "no match" error if there are no files in the current (or specified folder) - to get around this we simply extend the expansion to include dot-files thus: * .* - this will always yield results since the files . and .. will always be present. So in csh we can use this construct ...
foreach file (* .*)
echo $file
end
如果你想过滤掉标准的点文件，那很简单…
foreach file (* .*)
if ("$file" == .) continue
if ("file" == ..) continue
echo $file
end
在这个线程的第一篇文章中的代码将这样写:-
getlist() {
for f in $(* .*)
do
echo "File found: $f"
# do something useful
done
}
希望这能有所帮助!
find . -iname "foo*" -print0 | xargs -L1 -0 echo "File found:"
