NSString *stringWithoutAsterisk(NSString *string) {
    NSRange asterisk = [string rangeOfString:@"*"];
    return asterisk.location == 0 ? [string substringFromIndex:1] : string;
}

使用characterAtIndex:。如果第一个字符是星号，使用substringFromIndex:获取不带'*'的字符串。

这可能有用吗?：）

http://developer.apple.com/mac/library/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html / / apple_ref / occ instm / NSString / characterAtIndex:

只需搜索索引为0的字符，并将其与您正在寻找的值进行比较!

你可以使用NSString的-hasPrefix:方法:

objective - c:

NSString* output = nil;
if([string hasPrefix:@"*"]) {
    output = [string substringFromIndex:1];
}

迅速:

var output:String?
if string.hasPrefix("*") {
    output = string.substringFromIndex(string.startIndex.advancedBy(1))
}

另一种方法。

希望它能帮助某人……

if ([[temp substringToIndex:4] isEqualToString:@"http"]) {
  //starts with http
}

这个漂亮的小代码是我偶然发现的，我还没有在Stack上看到它的建议。它只在你想删除或修改的字符存在的情况下才有效，这在很多情况下都很方便。如果字符/s不存在，它不会改变你的NSString:

NSString = [yourString stringByReplacingOccurrencesOfString:@"YOUR CHARACTERS YOU WANT TO REMOVE" withString:@"CAN either be EMPTY or WITH TEXT REPLACEMENT"];

我是这样使用它的:

//declare what to look for
NSString * suffixTorRemove = @"</p>";
NSString * prefixToRemove = @"<p>";
NSString * randomCharacter = @"</strong>";
NSString * moreRandom = @"<strong>";
NSString * makeAndSign = @"&";

//I AM INSERTING A VALUE FROM A DATABASE AND HAVE ASSIGNED IT TO returnStr
returnStr = [returnStr stringByReplacingOccurrencesOfString:suffixTorRemove withString:@""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:prefixToRemove withString:@""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:randomCharacter withString:@""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:moreRandom withString:@""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:makeAndSign withString:@"&"];

//check the output
NSLog(@"returnStr IS NOW: %@", returnStr);

这一行超级简单，可以同时执行三个动作:

检查字符串中不需要的字符 可以替换成你喜欢的任何东西吗 不影响周围的代码