如何在Python中获得以毫秒为单位的当前时间?
当前回答
对于Python 3.7+, time.time_ns()给出自epoch以来以纳秒为单位经过的时间。
这给出了以毫秒为单位的整数时间:
import time
ms = time.time_ns() // 1_000_000
其他回答
def TimestampMillisec64():
return int((datetime.datetime.utcnow() - datetime.datetime(1970, 1, 1)).total_seconds() * 1000)
unix诞生的时间
from time import time
while True:
print(str(time()*1000)+'ms \r', end='')
程序开始的时间
from time import time
init = time()
while True:
print(str((time()-init)*1000)+'ms \r', end='')
谢谢你的宝贵时间
更新:感谢@neuralmer。
最有效的方法之一:
(time.time_ns() + 500000) // 1000000 #rounding last digit (1ms digit)
or
time.time_ns() // 1000000 #flooring last digit (1ms digit)
在其他方法中,这两种方法都非常有效。
基准:
你可以在我自己的机器上看到一些不同方法的基准测试结果:
import time
t = time.perf_counter_ns()
for i in range(1000):
o = time.time_ns() // 1000000 #each 200 ns
t2 = time.perf_counter_ns()
print((t2 - t)//1000)
t = time.perf_counter_ns()
for i in range(1000):
o = (time.time_ns() + 500000) // 1000000 #each 227 ns
t2 = time.perf_counter_ns()
print((t2 - t)//1000)
t = time.perf_counter_ns()
for i in range(1000):
o = round(time.time_ns() / 1000000) #each 456 ns
t2 = time.perf_counter_ns()
print((t2 - t)//1000)
t = time.perf_counter_ns()
for i in range(1000):
o = int(time.time_ns() / 1000000) #each 467 ns
t2 = time.perf_counter_ns()
print((t2 - t)//1000)
t = time.perf_counter_ns()
for i in range(1000):
o = int(time.time()* 1000) #each 319 ns
t2 = time.perf_counter_ns()
print((t2 - t)//1000)
t = time.perf_counter_ns()
for i in range(1000):
o = round(time.time()* 1000) #each 342 ns
t2 = time.perf_counter_ns()
print((t2 - t)//1000)```
使用time.time ():
import time
def current_milli_time():
return round(time.time() * 1000)
然后:
>>> current_milli_time()
1378761833768
我发现的以毫秒为单位获取当前UTC时间的最简单方法是:
# timeutil.py
import datetime
def get_epochtime_ms():
return round(datetime.datetime.utcnow().timestamp() * 1000)
# sample.py
import timeutil
timeutil.get_epochtime_ms()