如何在PHP中获得字符串的前n个字符?什么是最快的方法来修剪一个字符串到特定的字符数,并添加'…如果需要的话?


当前回答

我为此开发了一个函数

 function str_short($string,$limit)
        {
            $len=strlen($string);
            if($len>$limit)
            {
             $to_sub=$len-$limit;
             $crop_temp=substr($string,0,-$to_sub);
             return $crop_len=$crop_temp."...";
            }
            else
            {
                return $string;
            }
        }

你只需要调用带有string和limit的函数 例如:str_short(“hahahahahah”,5); 它会剪掉你的绳子,并在最后加上“…” :)

其他回答

要在函数内创建(用于重复使用)并动态限制长度,请使用:

function string_length_cutoff($string, $limit, $subtext = '...')
{
    return (strlen($string) > $limit) ? substr($string, 0, ($limit-strlen(subtext))).$subtext : $string;
}

// example usage:
echo string_length_cutoff('Michelle Lee Hammontree-Garcia', 26);

// or (for custom substitution text
echo string_length_cutoff('Michelle Lee Hammontree-Garcia', 26, '..');

如果对截断字符串的长度没有硬性要求,可以使用这个来截断并防止截断最后一个单词:

$text = "Knowledge is a natural right of every human being of which no one
has the right to deprive him or her under any pretext, except in a case where a
person does something which deprives him or her of that right. It is mere
stupidity to leave its benefits to certain individuals and teams who monopolize
these while the masses provide the facilities and pay the expenses for the
establishment of public sports.";

// we don't want new lines in our preview
$text_only_spaces = preg_replace('/\s+/', ' ', $text);

// truncates the text
$text_truncated = mb_substr($text_only_spaces, 0, mb_strpos($text_only_spaces, " ", 50));

// prevents last word truncation
$preview = trim(mb_substr($text_truncated, 0, mb_strrpos($text_truncated, " ")));

在本例中,$preview将是“Knowledge is a natural right of every human”。

动态代码示例: http://sandbox.onlinephpfunctions.com/code/25484a8b687d1f5ad93f62082b6379662a6b4713

$yourString = "bla blaaa bla blllla bla bla";
$out = "";
if(strlen($yourString) > 22) {
    while(strlen($yourString) > 22) {
        $pos = strrpos($yourString, " ");
        if($pos !== false && $pos <= 22) {
            $out = substr($yourString,0,$pos);
            break;
        } else {
            $yourString = substr($yourString,0,$pos);
            continue;
        }
    }
} else {
    $out = $yourString;
}
echo "Output String: ".$out;

我使用的函数是:

function cutAfter($string, $len = 30, $append = '...') {
        return (strlen($string) > $len) ? 
          substr($string, 0, $len - strlen($append)) . $append : 
          $string;
}

看到它的行动。

我不确定这是否是最快的解决方案,但它看起来是最短的:

$result = current(explode("\n", wordwrap($str, $width, "...\n")));

附注:见一些例子在这里https://stackoverflow.com/a/17852480/131337