之前我只是检查一个空值，这实际上是错误的。

    $data = "ahad";
    $r_data = json_decode($data);
    if($r_data){//json_decode will return null, which is the behavior we expect
        //success
    }

上面的代码可以很好地处理字符串。然而，只要我提供号码，它就中断了。为例。

    $data = "1213145";
    $r_data = json_decode($data);

    if($r_data){//json_decode will return 1213145, which is the behavior we don't expect
        //success
    }

要修复它，我所做的很简单。

    $data = "ahad";
    $r_data = json_decode($data);

    if(($r_data != $data) && $r_data)
        print "Json success";
    else
        print "Json error";

使用PHPBench和下面的类，得到了以下结果:

<?php

declare(strict_types=1);

/**
 * @Revs(1000)
 * @Iterations(100)
 */
class BenchmarkJson
{
    public function benchCatchValid(): bool
    {
        $validJson = '{"validJson":true}';
        try {
            json_decode($validJson, true, 512, JSON_THROW_ON_ERROR);
            return true;
        } catch(\JsonException $exception) {}
        return false;
    }

    public function benchCatchInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        try {
            json_decode($invalidJson, true, 512, JSON_THROW_ON_ERROR);
            return true;
        } catch(\JsonException $exception) {}
        return false;
    }

    public function benchLastErrorValid(): bool
    {
        $validJson = '{"validJson":true}';
        json_decode($validJson, true);
        return (json_last_error() === JSON_ERROR_NONE);
    }

    public function benchLastErrorInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        json_decode($invalidJson, true);
        return (json_last_error() === JSON_ERROR_NONE);
    }

    public function benchNullValid(): bool
    {
        $validJson = '{"validJson":true}';
        return (json_decode($validJson, true) !== null);
    }

    public function benchNullInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        return (json_decode($invalidJson, true) !== null);
    }
}

6 subjects, 600 iterations, 6,000 revs, 0 rejects, 0 failures, 0 warnings
(best [mean mode] worst) = 0.714 [1.203 1.175] 1.073 (μs)
⅀T: 721.504μs μSD/r 0.089μs μRSD/r: 7.270%
suite: 1343ab9a3590de6065bc0bc6eeb344c9f6eba642, date: 2020-01-21, stime: 12:50:14
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| benchmark     | subject               | set | revs | its | mem_peak   | best    | mean    | mode    | worst   | stdev   | rstdev | diff  |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| BenchmarkJson | benchCatchValid       | 0   | 1000 | 100 | 2,980,168b | 0.954μs | 1.032μs | 1.016μs | 1.428μs | 0.062μs | 6.04%  | 1.33x |
| BenchmarkJson | benchCatchInvalid     | 0   | 1000 | 100 | 2,980,184b | 2.033μs | 2.228μs | 2.166μs | 3.001μs | 0.168μs | 7.55%  | 2.88x |
| BenchmarkJson | benchLastErrorValid   | 0   | 1000 | 100 | 2,980,184b | 1.076μs | 1.195μs | 1.169μs | 1.616μs | 0.083μs | 6.97%  | 1.54x |
| BenchmarkJson | benchLastErrorInvalid | 0   | 1000 | 100 | 2,980,184b | 0.785μs | 0.861μs | 0.863μs | 1.132μs | 0.056μs | 6.54%  | 1.11x |
| BenchmarkJson | benchNullValid        | 0   | 1000 | 100 | 2,980,168b | 0.985μs | 1.124μs | 1.077μs | 1.731μs | 0.114μs | 10.15% | 1.45x |
| BenchmarkJson | benchNullInvalid      | 0   | 1000 | 100 | 2,980,184b | 0.714μs | 0.775μs | 0.759μs | 1.073μs | 0.049μs | 6.36%  | 1.00x |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+

结论:检查json是否有效的最快方法是返回json_decode($json, true) !== null)。

您必须验证您的输入，以确保您传递的字符串不是空的，实际上是一个字符串。空字符串不是有效的JSON。

function is_json($string) {
  return !empty($string) && is_string($string) && is_array(json_decode($string, true)) && json_last_error() == 0;
}

我认为在PHP中更重要的是确定JSON对象是否有数据，因为要使用数据，您将需要调用json_encode()或json_decode()。我建议拒绝空JSON对象，这样就不必在空数据上运行编码和解码。

function has_json_data($string) {
  $array = json_decode($string, true);
  return !empty($string) && is_string($string) && is_array($array) && !empty($array) && json_last_error() == 0;
}

function isJson($string) {
   json_decode($string);
   return json_last_error() === JSON_ERROR_NONE;
}

我的另一个建议:)

function isJson(string $string) {
  return ($result = json_decode($string, true)) ? $result : $string;
}

另一种简单的方法

function is_json($str)
{
    return is_array(json_decode($str,true));
}