平台架构不是可靠的方法。 相反,我们:

$ arch -i386 /usr/local/bin/python2.7
Python 2.7.9 (v2.7.9:648dcafa7e5f, Dec 10 2014, 10:10:46)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import platform, sys
>>> platform.architecture(), sys.maxsize
(('64bit', ''), 2147483647)
>>> ^D
$ arch -x86_64 /usr/local/bin/python2.7
Python 2.7.9 (v2.7.9:648dcafa7e5f, Dec 10 2014, 10:10:46)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import platform, sys
>>> platform.architecture(), sys.maxsize
(('64bit', ''), 9223372036854775807)

根据abe32的回答，

import sys
n_bits = 32 << bool(sys.maxsize >> 32)

N_bits将有32或64位。

基本上是Matthew Marshall答案的变体(使用来自std.library的struct):

import struct
print struct.calcsize("P") * 8

Windows 10操作系统

打开cmd终端，输入如下图所示的>python启动python解释器

如果解释器信息在开始时包含AMD64，则为64位，否则为32位。

当在终端/命令行中启动Python解释器时，你可能还会看到这样一行:

win32上的Python 2.7.2(默认，2011年6月12日，14:24:46)[MSC v.1500 64位(AMD64)]

其中[MSC v.1500 64位(AMD64)]表示64位Python。 适用于我的特定设置。

平台架构不是可靠的方法。 相反,我们:

$ arch -i386 /usr/local/bin/python2.7
Python 2.7.9 (v2.7.9:648dcafa7e5f, Dec 10 2014, 10:10:46)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import platform, sys
>>> platform.architecture(), sys.maxsize
(('64bit', ''), 2147483647)
>>> ^D
$ arch -x86_64 /usr/local/bin/python2.7
Python 2.7.9 (v2.7.9:648dcafa7e5f, Dec 10 2014, 10:10:46)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import platform, sys
>>> platform.architecture(), sys.maxsize
(('64bit', ''), 9223372036854775807)