是否有可能在JavaScript中检测“空闲”时间?
我的主要用例可能是预取或预加载内容。
我将空闲时间定义为用户不活动或没有任何CPU使用的时间段
是否有可能在JavaScript中检测“空闲”时间?
我的主要用例可能是预取或预加载内容。
我将空闲时间定义为用户不活动或没有任何CPU使用的时间段
当前回答
改进Equiman(原始)的答案:
function idleLogout() {
var t;
window.onload = resetTimer;
window.onmousemove = resetTimer;
window.onmousedown = resetTimer; // catches touchscreen presses as well
window.ontouchstart = resetTimer; // catches touchscreen swipes as well
window.ontouchmove = resetTimer; // required by some devices
window.onclick = resetTimer; // catches touchpad clicks as well
window.onkeydown = resetTimer;
window.addEventListener('scroll', resetTimer, true); // improved; see comments
function yourFunction() {
// your function for too long inactivity goes here
// e.g. window.location.href = 'logout.php';
}
function resetTimer() {
clearTimeout(t);
t = setTimeout(yourFunction, 10000); // time is in milliseconds
}
}
idleLogout();
除了活动检测方面的改进,以及从文档到窗口的更改之外,这个脚本实际上调用了函数,而不是让它闲置着。
它不会直接捕获零CPU使用情况,但这是不可能的,因为执行函数会导致CPU使用。用户不活动最终导致CPU使用率为零,因此它间接地捕捉到CPU使用率为零。
其他回答
对于其他有同样问题的用户。这是我刚编的一个函数。
它不会在用户每次鼠标移动时运行,也不会在每次鼠标移动时清除计时器。
<script>
// Timeout in seconds
var timeout = 10; // 10 seconds
// You don't have to change anything below this line, except maybe
// the alert('Welcome back!') :-)
// ----------------------------------------------------------------
var pos = '', prevpos = '', timer = 0, interval = timeout / 5 * 1000;
timeout = timeout * 1000 - interval;
function mouseHasMoved(e){
document.onmousemove = null;
prevpos = pos;
pos = e.pageX + '+' + e.pageY;
if(timer > timeout){
timer = 0;
alert('Welcome back!');
}
}
setInterval(function(){
if(pos == prevpos){
timer += interval;
}else{
timer = 0;
prevpos = pos;
}
document.onmousemove = function(e){
mouseHasMoved(e);
}
}, interval);
</script>
纯JavaScript,通过addEventListener正确设置重置时间和绑定:
(function() {
var t,
timeout = 5000;
function resetTimer() {
console.log("reset: " + new Date().toLocaleString());
if (t) {
window.clearTimeout(t);
}
t = window.setTimeout(logout, timeout);
}
function logout() {
console.log("done: " + new Date().toLocaleString());
}
resetTimer();
//And bind the events to call `resetTimer()`
["click", "mousemove", "keypress"].forEach(function(name) {
console.log(name);
document.addEventListener(name, resetTimer);
});
}());
以下是我找到的最佳解决方案:
当用户空闲时发生火灾事件
下面是JavaScript代码:
idleTimer = null;
idleState = false;
idleWait = 2000;
(function ($) {
$(document).ready(function () {
$('*').bind('mousemove keydown scroll', function () {
clearTimeout(idleTimer);
if (idleState == true) {
// Reactivated event
$("body").append("<p>Welcome Back.</p>");
}
idleState = false;
idleTimer = setTimeout(function () {
// Idle Event
$("body").append("<p>You've been idle for " + idleWait/1000 + " seconds.</p>");
idleState = true; }, idleWait);
});
$("body").trigger("mousemove");
});
}) (jQuery)
改进Equiman(原始)的答案:
function idleLogout() {
var t;
window.onload = resetTimer;
window.onmousemove = resetTimer;
window.onmousedown = resetTimer; // catches touchscreen presses as well
window.ontouchstart = resetTimer; // catches touchscreen swipes as well
window.ontouchmove = resetTimer; // required by some devices
window.onclick = resetTimer; // catches touchpad clicks as well
window.onkeydown = resetTimer;
window.addEventListener('scroll', resetTimer, true); // improved; see comments
function yourFunction() {
// your function for too long inactivity goes here
// e.g. window.location.href = 'logout.php';
}
function resetTimer() {
clearTimeout(t);
t = setTimeout(yourFunction, 10000); // time is in milliseconds
}
}
idleLogout();
除了活动检测方面的改进,以及从文档到窗口的更改之外,这个脚本实际上调用了函数,而不是让它闲置着。
它不会直接捕获零CPU使用情况,但这是不可能的,因为执行函数会导致CPU使用。用户不活动最终导致CPU使用率为零,因此它间接地捕捉到CPU使用率为零。
您可以使用下面提到的解决方案
var idleTime;
$(document).ready(function () {
reloadPage();
$('html').bind('mousemove click mouseup mousedown keydown keypress keyup submit change mouseenter scroll resize dblclick', function () {
clearTimeout(idleTime);
reloadPage();
});
});
function reloadPage() {
clearTimeout(idleTime);
idleTime = setTimeout(function () {
location.reload();
}, 3000);
}