这个问题最初是针对Android 1.6提出的。
我正在我的应用程序中的照片选项。
我的Activity中有一个按钮和一个ImageView。当我点击按钮,它会重定向到图库,我将能够选择一个图像。所选的图像将出现在我的ImageView中。
这个问题最初是针对Android 1.6提出的。
我正在我的应用程序中的照片选项。
我的Activity中有一个按钮和一个ImageView。当我点击按钮,它会重定向到图库,我将能够选择一个图像。所选的图像将出现在我的ImageView中。
当前回答
private static final int SELECT_PHOTO = 100;
开始的目的
Intent photoPickerIntent = new Intent(Intent.ACTION_PICK);
photoPickerIntent.setType("image/*");
startActivityForResult(photoPickerIntent, SELECT_PHOTO);
过程的结果
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
super.onActivityResult(requestCode, resultCode, imageReturnedIntent);
switch(requestCode) {
case SELECT_PHOTO:
if(resultCode == RESULT_OK){
Uri selectedImage = imageReturnedIntent.getData();
InputStream imageStream = getContentResolver().openInputStream(selectedImage);
Bitmap yourSelectedImage = BitmapFactory.decodeStream(imageStream);
}
}
}
或者,你也可以降低你的图像样本,以避免OutOfMemory错误。
private Bitmap decodeUri(Uri selectedImage) throws FileNotFoundException {
// Decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(getContentResolver().openInputStream(selectedImage), null, o);
// The new size we want to scale to
final int REQUIRED_SIZE = 140;
// Find the correct scale value. It should be the power of 2.
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE) {
break;
}
width_tmp /= 2;
height_tmp /= 2;
scale *= 2;
}
// Decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeStream(getContentResolver().openInputStream(selectedImage), null, o2);
}
其他回答
像-一样调用chooseImage方法
public void chooseImage(ImageView v)
{
Intent intent = new Intent(Intent.ACTION_PICK);
intent.setType("image/*");
startActivityForResult(intent, SELECT_PHOTO);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, imageReturnedIntent);
if(imageReturnedIntent != null)
{
Uri selectedImage = imageReturnedIntent.getData();
switch(requestCode) {
case SELECT_PHOTO:
if(resultCode == RESULT_OK)
{
Bitmap datifoto = null;
temp.setImageBitmap(null);
Uri picUri = null;
picUri = imageReturnedIntent.getData();//<- get Uri here from data intent
if(picUri !=null){
try {
datifoto = android.provider.MediaStore.Images.Media.getBitmap(this.getContentResolver(), picUri);
temp.setImageBitmap(datifoto);
} catch (FileNotFoundException e) {
throw new RuntimeException(e);
} catch (IOException e) {
throw new RuntimeException(e);
} catch (OutOfMemoryError e) {
Toast.makeText(getBaseContext(), "Image is too large. choose other", Toast.LENGTH_LONG).show();
}
}
}
break;
}
}
else
{
//Toast.makeText(getBaseContext(), "data null", Toast.LENGTH_SHORT).show();
}
}
你必须为一个结果开始画廊意图。
Intent i = new Intent(Intent.ACTION_PICK,
android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(i, ACTIVITY_SELECT_IMAGE);
然后在onActivityForResult中调用intent.getData()来获取图像的Uri。然后你需要从ContentProvider中获取图像。
这样做可以启动图库,并允许用户选择一张图片:
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType("image/*");
startActivityForResult(intent, IMAGE_PICK);
然后在onActivityResult()中使用返回的图像的URI来设置ImageView上的图像。
这是一个图像和视频的测试代码。它也适用于所有小于19和大于19的api。
图片:
if (Build.VERSION.SDK_INT <= 19) {
Intent i = new Intent();
i.setType("image/*");
i.setAction(Intent.ACTION_GET_CONTENT);
i.addCategory(Intent.CATEGORY_OPENABLE);
startActivityForResult(i, 10);
} else if (Build.VERSION.SDK_INT > 19) {
Intent intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(intent, 10);
}
视频:
if (Build.VERSION.SDK_INT <= 19) {
Intent i = new Intent();
i.setType("video/*");
i.setAction(Intent.ACTION_GET_CONTENT);
i.addCategory(Intent.CATEGORY_OPENABLE);
startActivityForResult(i, 20);
} else if (Build.VERSION.SDK_INT > 19) {
Intent intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Video.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(intent, 20);
}
.
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (resultCode == Activity.RESULT_OK) {
if (requestCode == 10) {
Uri selectedImageUri = data.getData();
String selectedImagePath = getRealPathFromURI(selectedImageUri);
} else if (requestCode == 20) {
Uri selectedVideoUri = data.getData();
String selectedVideoPath = getRealPathFromURI(selectedVideoUri);
}
}
}
public String getRealPathFromURI(Uri uri) {
if (uri == null) {
return null;
}
String[] projection = {MediaStore.Images.Media.DATA};
Cursor cursor = getActivity().getContentResolver().query(uri, projection, null, null, null);
if (cursor != null) {
int column_index = cursor
.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
return uri.getPath();
}
由于某些原因,这个线程中的所有答案,在onActivityResult()中尝试对接收到的Uri进行后处理,比如获得图像的真实路径,然后使用BitmapFactory.decodeFile(path)来获得位图。
此步骤无需执行。ImageView类有一个叫做setImageURI(uri)的方法。将您的uri传递给它,您就应该完成了。
Uri imageUri = data.getData();
imageView.setImageURI(imageUri);
完整的工作示例可以在这里查看:http://androidbitmaps.blogspot.com/2015/04/loading-images-in-android-part-iii-pick.html
PS: 在要加载的图像太大而无法装入内存的情况下,在一个单独的变量中获取位图是有意义的,并且需要一个缩小操作来防止OurOfMemoryError,就像@siamii答案中所示的那样。