现在我们可以使用Intl了。Collator API现在创建数值比较器。浏览器支持是相当不错的，但在撰写本文时，Node.js还不支持。

const semverCompare = new Intl。Collator("en"， {numeric: true}).compare; const版本=[1.0.1,“1.10.2”,“1.1.1”,‘1.10.1’,‘1.5.10’,‘2.10.0’,‘2.0.1’); console.log (versions.sort (semverCompare)) const example2 =(“1.0”,“1.0.1”,“2.0”,“2.0.0.1”,“2.0.1”); console.log (example2.sort (semverCompare))

我根据Kons的想法做了这个，并针对Java版本“1.7.0_45”进行了优化。它只是一个将版本字符串转换为浮点数的函数。这是函数:

function parseVersionFloat(versionString) {
    var versionArray = ("" + versionString)
            .replace("_", ".")
            .replace(/[^0-9.]/g, "")
            .split("."),
        sum = 0;
    for (var i = 0; i < versionArray.length; ++i) {
        sum += Number(versionArray[i]) / Math.pow(10, i * 3);
    }
    console.log(versionString + " -> " + sum);
    return sum;
}

字符串“1.7.0_45”被转换为1.0070000450000001，这足以进行正常的比较。这里解释的错误:如何处理JavaScript中的浮点数精度?如果需要超过3个数字在任何部分，你可以改变除法数学。Pow (10, I * 3);;

输出如下所示:

1.7.0_45         > 1.007000045
ver 1.7.build_45 > 1.007000045
1.234.567.890    > 1.23456789

现在我们可以使用Intl了。Collator API现在创建数值比较器。浏览器支持是相当不错的，但在撰写本文时，Node.js还不支持。

const semverCompare = new Intl。Collator("en"， {numeric: true}).compare; const版本=[1.0.1,“1.10.2”,“1.1.1”,‘1.10.1’,‘1.5.10’,‘2.10.0’,‘2.0.1’); console.log (versions.sort (semverCompare)) const example2 =(“1.0”,“1.0.1”,“2.0”,“2.0.0.1”,“2.0.1”); console.log (example2.sort (semverCompare))

功能简单简短:

function isNewerVersion (oldVer, newVer) {
  const oldParts = oldVer.split('.')
  const newParts = newVer.split('.')
  for (var i = 0; i < newParts.length; i++) {
    const a = ~~newParts[i] // parse int
    const b = ~~oldParts[i] // parse int
    if (a > b) return true
    if (a < b) return false
  }
  return false
}

测试:

isNewerVersion('1.0', '2.0') // true
isNewerVersion('1.0', '1.0.1') // true
isNewerVersion('1.0.1', '1.0.10') // true
isNewerVersion('1.0.1', '1.0.1') // false
isNewerVersion('2.0', '1.0') // false
isNewerVersion('2', '1.0') // false
isNewerVersion('2.0.0.0.0.1', '2.1') // true
isNewerVersion('2.0.0.0.0.1', '2.0') // false

我不喜欢任何一个解决方案，所以我根据自己的编码偏好重新编写了它。请注意，最后四个检查结果与接受的答案略有不同。对我有用。

function v_check(version_a, version_b) {
    // compares version_a as it relates to version_b
    // a = b => "same"
    // a > b => "larger"
    // a < b => "smaller"
    // NaN   => "invalid"

    const arr_a = version_a.split('.');
    const arr_b = version_b.split('.');

    let result = "same"; // initialize to same // loop tries to disprove

    // loop through a and check each number against the same position in b
    for (let i = 0; i < arr_a.length; i++) {
        let a = arr_a[i];
        let b = arr_b[i];

        // same up to this point so if a is not there, a is smaller
        if (typeof a === 'undefined') {
            result = "smaller";
            break;

        // same up to this point so if b is not there, a is larger
        } else if (typeof b === 'undefined') {
            result = "larger";
            break;

        // otherwise, compare the two numbers
        } else {

            // non-positive numbers are invalid
            if (a >= 0 && b >= 0) {

                if (a < b) {
                    result = "smaller";
                    break;
                }
                else if (a > b) {
                    result = "larger";
                    break;
                }

            } else {
                result = "invalid";
                break;
            }
        }
    }

    // account for the case where the loop ended but there was still a position in b to evaluate
    if (result == "same" && arr_b.length > arr_a.length) result = "smaller";

    return result;
}


console.log(v_check("1.7.1", "1.7.10"));  // smaller
console.log(v_check("1.6.1", "1.7.10"));  // smaller
console.log(v_check("1.6.20", "1.7.10")); // smaller
console.log(v_check("1.7.1", "1.7.10"));  // smaller
console.log(v_check("1.7", "1.7.0"));     // smaller
console.log(v_check("1.7", "1.8.0"));     // smaller

console.log(v_check("1.7.10", "1.7.1"));  // larger
console.log(v_check("1.7.10", "1.6.1"));  // larger
console.log(v_check("1.7.10", "1.6.20")); // larger
console.log(v_check("1.7.0", "1.7"));     // larger
console.log(v_check("1.8.0", "1.7"));     // larger

console.log(v_check("1.7.10", "1.7.10")); // same
console.log(v_check("1.7", "1.7"));       // same

console.log(v_check("1.7", "1..7")); // larger
console.log(v_check("1.7", "Bad"));  // invalid
console.log(v_check("1..7", "1.7")); // smaller
console.log(v_check("Bad", "1.7"));  // invalid

2017答:

v1 = '20.0.12'; 
v2 = '3.123.12';

compareVersions(v1,v2) 
// return positive: v1 > v2, zero:v1 == v2, negative: v1 < v2 
function compareVersions(v1, v2) {
        v1= v1.split('.')
        v2= v2.split('.')
        var len = Math.max(v1.length,v2.length)
        /*default is true*/
        for( let i=0; i < len; i++)
            v1 = Number(v1[i] || 0);
            v2 = Number(v2[i] || 0);
            if (v1 !== v2) return v1 - v2 ;
            i++;
        }
        return 0;
    }

最简单的现代浏览器代码:

 function compareVersion2(ver1, ver2) {
      ver1 = ver1.split('.').map( s => s.padStart(10) ).join('.');
      ver2 = ver2.split('.').map( s => s.padStart(10) ).join('.');
      return ver1 <= ver2;
 }

这里的想法是比较数字，但以字符串的形式。为了使比较工作，两个字符串必须在相同的长度。所以:

"123" > "99"变成"123" > "099" 填充短数字“修复”比较

这里我用0填充每个部分，长度为10。然后使用简单的字符串比较来得到答案

例子:

var ver1 = '0.2.10', ver2=`0.10.2`
//become 
ver1 = '0000000000.0000000002.0000000010'
ver2 = '0000000000.0000000010.0000000002'
// then it easy to see that
ver1 <= ver2 // true