我正在做一些SQL选择查询,并希望将我的UTC日期时间列转换为本地时间,以便在我的查询结果中显示为本地时间。注意,我不希望通过代码进行这种转换,而是当我对我的数据库进行手动和随机SQL查询时。


当前回答

如果你需要一个转换而不是你的服务器位置,这里有一个函数,允许你传递一个标准偏移量,并考虑美国夏令时:

-- =============================================
-- Author:      Ron Smith
-- Create date: 2013-10-23
-- Description: Converts UTC to DST
--              based on passed Standard offset
-- =============================================
CREATE FUNCTION [dbo].[fn_UTC_to_DST]
(
    @UTC datetime,
    @StandardOffset int
)
RETURNS datetime
AS
BEGIN

    declare 
        @DST datetime,
        @SSM datetime, -- Second Sunday in March
        @FSN datetime  -- First Sunday in November

    -- get DST Range
    set @SSM = datename(year,@UTC) + '0314' 
    set @SSM = dateadd(hour,2,dateadd(day,datepart(dw,@SSM)*-1+1,@SSM))
    set @FSN = datename(year,@UTC) + '1107'
    set @FSN = dateadd(second,-1,dateadd(hour,2,dateadd(day,datepart(dw,@FSN)*-1+1,@FSN)))

    -- add an hour to @StandardOffset if @UTC is in DST range
    if @UTC between @SSM and @FSN
        set @StandardOffset = @StandardOffset + 1

    -- convert to DST
    set @DST = dateadd(hour,@StandardOffset,@UTC)

    -- return converted datetime
    return @DST

END

GO

其他回答

罗恩的回答有一个错误。它使用当地时间凌晨2:00,其中需要UTC等效值。我没有足够的声望分数来评论Ron的回答,所以更正版本如下:

-- =============================================
-- Author:      Ron Smith
-- Create date: 2013-10-23
-- Description: Converts UTC to DST
--              based on passed Standard offset
-- =============================================
CREATE FUNCTION [dbo].[fn_UTC_to_DST]
(
    @UTC datetime,
    @StandardOffset int
)
RETURNS datetime
AS
BEGIN

declare 
    @DST datetime,
    @SSM datetime, -- Second Sunday in March
    @FSN datetime  -- First Sunday in November
-- get DST Range
set @SSM = datename(year,@UTC) + '0314' 
set @SSM = dateadd(hour,2 - @StandardOffset,dateadd(day,datepart(dw,@SSM)*-1+1,@SSM))
set @FSN = datename(year,@UTC) + '1107'
set @FSN = dateadd(second,-1,dateadd(hour,2 - (@StandardOffset + 1),dateadd(day,datepart(dw,@FSN)*-1+1,@FSN)))

-- add an hour to @StandardOffset if @UTC is in DST range
if @UTC between @SSM and @FSN
    set @StandardOffset = @StandardOffset + 1

-- convert to DST
set @DST = dateadd(hour,@StandardOffset,@UTC)

-- return converted datetime
return @DST

END

这样就可以获得与夏令时同步的服务器时间

declare @dt datetime
set @dt = getutcdate() -- GMT equivalent

sysdatetimeoffset会考虑夏令时

select [InputTime] = @dt
       , [LocalTime2] = dateadd(mi, datediff(mi, sysdatetimeoffset(),getdate()), @dt) 

您必须重新格式化字符串以及转换为正确的时间。在这种情况下,我需要祖鲁时间。

Declare @Date datetime;
Declare @DateString varchar(50);
set @Date = GETDATE(); 
declare @ZuluTime datetime;

Declare @DateFrom varchar (50);
Declare @DateTo varchar (50);
set @ZuluTime = DATEADD(second, DATEDIFF(second, GETDATE(), GETUTCDATE()), @Date);
set @DateString =  FORMAT(@ZuluTime, 'yyyy-MM-ddThh:mm:ssZ', 'en-US' )  
select @DateString;

下面是一个将夏令时考虑在内的更简单的例子

CREATE FUNCTION [dbo].[UtcToLocal] 
(
    @p_utcDatetime DATETIME 
)
RETURNS DATETIME
AS
BEGIN
    RETURN DATEADD(MINUTE, DATEDIFF(MINUTE, GETUTCDATE(), @p_utcDatetime), GETDATE())
END

我使用switchoffset将utc时间转换为本地时间。时区偏移可以通过使用datename(tzoffset,systemdatetimeoffset())来确定。同样地,如果您想获得经过的时间,则使用getutcdate将时间保持为datediff函数的utc时间。

select
      ,[Field1]
      ,Format(SWITCHOFFSET([MyDateOnUTC],DATENAME(TZOFFSET, SYSDATETIMEOFFSET())),'MM/dd/yyyy hh:mm:ss tt')  UtcToLocalTime
      ,datediff(minute,[ClaimedOnUTC],getutcdate()) ElapsedMinutes
 from dbo.my_table