我正在做一些SQL选择查询,并希望将我的UTC日期时间列转换为本地时间,以便在我的查询结果中显示为本地时间。注意,我不希望通过代码进行这种转换,而是当我对我的数据库进行手动和随机SQL查询时。
当前回答
使用新的SQL Server 2016机会:
CREATE FUNCTION ToLocalTime(@dtUtc datetime, @timezoneId nvarchar(256))
RETURNS datetime
AS BEGIN
return @dtUtc AT TIME ZONE 'UTC' AT TIME ZONE @timezoneId
/* -- second way, faster
return SWITCHOFFSET(@dtUtc , DATENAME(tz, @dtUtc AT TIME ZONE @timezoneId))
*/
/* -- third way
declare @dtLocal datetimeoffset
set @dtLocal = @dtUtc AT TIME ZONE @timezoneId
return dateadd(minute, DATEPART (TZoffset, @dtLocal), @dtUtc)
*/
END
GO
但clr程序的工作速度快5倍:'-(
请注意,一个时区的偏移量可以更改为冬季时间或夏季时间。例如
select cast('2017-02-08 09:00:00.000' as datetime) AT TIME ZONE 'Eastern Standard Time'
select cast('2017-08-08 09:00:00.000' as datetime) AT TIME ZONE 'Eastern Standard Time'
结果:
2017-02-08 09:00:00.000 -05:00
2017-08-08 09:00:00.000 -04:00
你不能只是添加常数偏移量。
其他回答
你可以在SQL Server 2008或更高版本上这样做:
SELECT CONVERT(datetime,
SWITCHOFFSET(CONVERT(datetimeoffset,
MyTable.UtcColumn),
DATENAME(TzOffset, SYSDATETIMEOFFSET())))
AS ColumnInLocalTime
FROM MyTable
你也可以用更简洁的方法:
SELECT DATEADD(mi, DATEDIFF(mi, GETUTCDATE(), GETDATE()), MyTable.UtcColumn)
AS ColumnInLocalTime
FROM MyTable
无论您做什么,都不要使用-来减去日期,因为该操作不是原子的,并且由于在不同时间(即非原子地)检查的系统datetime和本地datetime之间的竞争条件,您有时会得到不确定的结果。
请注意,这个答案没有考虑夏令时。如果你想包含夏令时调整,也请参阅以下SO问题:
如何在SQL Server中创建夏令时开始和结束函数
最简单的答案并不总是在底部,但这一次是,并且可以在上面的评论中看到。 使用您自己的“AT TIME ZONE”来捕获列/数据字段的TzOffset,而不是当前的SYSDATETIME。 在下面的数据中,2个查询,一个关于feb数据(DST是关闭的,在阿姆斯特丹的冬天)+1差异 第二次查询阿姆斯特丹4月份的数据,所以+2小时的差异。
select top 2 month(receiveTimeUTC) as MonthInWinterOrSpring
, receiveTimeUTC
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, SYSDATETIMEOFFSET()))) as LocalTimeWrongNoDST
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, receiveTimeUTC AT TIME ZONE 'Central European Standard Time' ))) as LocalTimeWithDST
from sensordetails order by id
select top 2 month(receiveTimeUTC) as MonthInWinterOrSpring, receiveTimeUTC
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, SYSDATETIMEOFFSET()))) as LocalTimeWrongNoDST
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, receiveTimeUTC AT TIME ZONE 'Central European Standard Time' ))) as LocalTimeWithDST
from sensordetails order by id desc
结果:
所以这是一个T-SQL (SQL Server Answer),不需要函数的storedproc。
对于任何仍然试图解决这个问题的人,这里有一个在SQL Server 2017中工作的概念证明
declare
@StartDate date = '2020-01-01'
;with cte_utc as
(
select
1 as i
,CONVERT(datetime, @StartDate) AS UTC
,datepart(weekday, CONVERT(datetime, @StartDate)) as Weekday
,datepart(month, CONVERT(datetime, @StartDate)) as [Month]
,datepart(YEAR, CONVERT(datetime, @StartDate)) as [Year]
union all
Select
i + 1
,dateadd(d, 1, utc)
,datepart(weekday, CONVERT(datetime, dateadd(d, 1, utc))) as Weekday
,datepart(month, CONVERT(datetime, dateadd(d, 1, utc))) as [Month]
,datepart(YEAR, CONVERT(datetime, dateadd(d, 1, utc))) as [Year]
from
cte_utc
where
(i + 1) < 32767
), cte_utc_dates as
(
select
*,
DENSE_RANK()OVER(PARTITION BY [Year], [Month], [Weekday] ORDER BY Utc) WeekDayIndex
from
cte_utc
), cte_hours as (
select 0 as [Hour]
union all
select [Hour] + 1 from cte_hours where [Hour] < 23
)
select
d.*
, DATEADD(hour, h.Hour, d.UTC) AS UtcTime
,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Central Standard Time') CST
,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Eastern Standard Time') EST
from
cte_utc_dates d, cte_hours h
where
([Month] = 3 and [Weekday] = 1 and WeekDayIndex = 2 )-- dst start
or
([Month] = 11 and [Weekday] = 1 and WeekDayIndex = 1 )-- dst end
order by
utc
OPTION (MAXRECURSION 32767)
GO
declare @mydate2 datetime
set @mydate2=Getdate()
select @mydate2 as mydate,
dateadd(minute, datediff(minute,getdate(),@mydate2),getutcdate())
我没有发现任何这些示例有助于将日期时间存储为UTC到指定时区(不是服务器的时区,因为Azure SQL数据库以UTC运行)中的日期时间。我是这样处理的。它并不优雅,但它很简单,无需维护其他表就能给出正确答案:
select CONVERT(datetime, SWITCHOFFSET(dateTimeField, DATEPART(TZOFFSET,
dateTimeField AT TIME ZONE 'Eastern Standard Time')))