我稍微修改了Bill Phillips提供的解决方案，以满足我的需要

private class PagerAdapter extends FragmentStatePagerAdapter{
    Bundle oBundle;
    FragmentManager oFragmentManager;
    ArrayList<Fragment> oPooledFragments;

public PagerAdapter(FragmentManager fm) {
    super(fm);
    oFragmentManager=fm;

    }
@Override
public int getItemPosition(Object object) {

    Fragment oFragment=(Fragment)object;
    oPooledFragments=new ArrayList<>(oFragmentManager.getFragments());
    if(oPooledFragments.contains(oFragment))
        return POSITION_NONE;
    else
        return POSITION_UNCHANGED;
    } 
}

因此，当getItemPosition被调用时，getItemPosition()只会为那些当前在FragmentManager中的片段返回POSITION_NONE。 (注意，这个FragmentStatePager和与之相关的ViewPager包含在一个Fragment中，而不是一个Activity中)

在代码中的notifyDataSetChanged()之后尝试在ViewPager上销毁drawingcache()。

我尝试了很多不同的方法，但没有一个能真正解决我的问题。下面是我如何用你们提供的混合解决方案来解决这个问题。谢谢每一个人。

class PagerAdapter extends FragmentPagerAdapter {

    public boolean flag_refresh=false;

    public PagerAdapter(FragmentManager fm) {
        super(fm);
    }

    @Override
    public Fragment getItem(int page) {
        FragmentsMain f;
        f=new FragmentsMain();
        f.page=page;
        return f;
    }

    @Override
    public int getCount() {
        return 4;
    }

    @Override
    public int getItemPosition(Object item) {
        int page= ((FragmentsMain)item).page;

        if (page == 0 && flag_refresh) {
            flag_refresh=false;
            return POSITION_NONE;
        } else {
            return super.getItemPosition(item);
        }
    }

    @Override
    public void destroyItem(View container, int position, Object object) {

        ((ViewPager) container).removeView((View) object);
    }
}

我只想在onResume()后刷新页面0。

 adapter=new PagerAdapter(getSupportFragmentManager());
 pager.setAdapter(adapter);

@Override
protected void onResume() {
    super.onResume();

    if (adapter!=null) {
        adapter.flag_refresh=true;
        adapter.notifyDataSetChanged();
    }
}

在我的FragmentsMain中，有一个公共整数“page”，它可以告诉我这是否是我想要刷新的页面。

public class FragmentsMain extends Fragment {

private Cursor cursor;
private static Context context;
public int page=-1;

我遇到过这个问题，今天终于解决了，所以我把我学到的东西写下来，希望对那些刚接触Android ViewPager并像我一样更新的人有帮助。我使用FragmentStatePagerAdapter在API级别17，目前只有2个片段。我想一定有什么地方不对，请指正，谢谢。

Serialized data has to be loaded into memory. This can be done using a CursorLoader/AsyncTask/Thread. Whether it's automatically loaded depends on your code. If you are using a CursorLoader, it's auto-loaded since there is a registered data observer. After you call viewpager.setAdapter(pageradapter), the adapter's getCount() is constantly called to build fragments. So if data is being loaded, getCount() can return 0, thus you don't need to create dummy fragments for no data shown. After the data is loaded, the adapter will not build fragments automatically since getCount() is still 0, so we can set the actually loaded data number to be returned by getCount(), then call the adapter's notifyDataSetChanged(). ViewPager begin to create fragments (just the first 2 fragments) by data in memory. It's done before notifyDataSetChanged() is returned. Then the ViewPager has the right fragments you need. If the data in the database and memory are both updated (write through), or just data in memory is updated (write back), or only data in the database is updated. In the last two cases if data is not automatically loaded from the database to memory (as mentioned above). The ViewPager and pager adapter just deal with data in memory. So when data in memory is updated, we just need to call the adapter's notifyDataSetChanged(). Since the fragment is already created, the adapter's onItemPosition() will be called before notifyDataSetChanged(） returns. Nothing needs to be done in getItemPosition(). Then the data is updated.

由于某种原因，没有一个答案对我有用，所以我不得不重写restoreState方法，而不调用我的fragmentStatePagerAdapter中的super。代码:

private class MyAdapter extends FragmentStatePagerAdapter {

    // [Rest of implementation]

    @Override
    public void restoreState(Parcelable state, ClassLoader loader) {}

}

这个解决方案并不适用于所有人，但在我的例子中，我的ViewPager中的每个Fragment都是一个不同的类，并且一次只存在其中一个。

有了这个约束，这个解决方案是安全的，应该可以安全地在生产中使用。

private void updateFragment(Item item) {

    List<Fragment> fragments = getSupportFragmentManager().getFragments();
    for (Fragment fragment : fragments) {

        if (fragment instanceof MyItemFragment && fragment.isVisible()) {
            ((MyItemFragment) fragment).update(item);
        }

    }
}

如果您有同一个片段的多个版本，您可以使用相同的策略来调用这些片段上的方法，以确定它是否是您希望更新的片段。