我有JavaScript,它周期性地执行活动。当用户没有在看站点时(例如,窗口或选项卡没有焦点),最好不要运行。

是否有一种方法可以使用JavaScript来做到这一点?

我的参考点:如果你正在使用的窗口不活跃,Gmail聊天就会播放声音。


当前回答

U可以使用:

(function () {

    var requiredResolution = 10; // ms
    var checkInterval = 1000; // ms
    var tolerance = 20; // percent


    var counter = 0;
    var expected = checkInterval / requiredResolution;
    //console.log('expected:', expected);

    window.setInterval(function () {
        counter++;
    }, requiredResolution);

    window.setInterval(function () {
        var deviation = 100 * Math.abs(1 - counter / expected);
        // console.log('is:', counter, '(off by', deviation , '%)');
        if (deviation > tolerance) {
            console.warn('Timer resolution not sufficient!');
        }
        counter = 0;
    }, checkInterval);

})();

其他回答

从最初编写这个答案开始,由于W3C,一个新的规范已经达到了推荐状态。页面可见性API(在MDN上)现在允许我们更准确地检测页面何时对用户隐藏。

document.addEventListener("visibilitychange", onchange);

当前浏览器支持:

铬13 + Internet Explorer 10+ Firefox 10 + Opera 12.10+[阅读笔记]

下面的代码在不兼容的浏览器中退回到不太可靠的模糊/聚焦方法:

(function() {
  var hidden = "hidden";

  // Standards:
  if (hidden in document)
    document.addEventListener("visibilitychange", onchange);
  else if ((hidden = "mozHidden") in document)
    document.addEventListener("mozvisibilitychange", onchange);
  else if ((hidden = "webkitHidden") in document)
    document.addEventListener("webkitvisibilitychange", onchange);
  else if ((hidden = "msHidden") in document)
    document.addEventListener("msvisibilitychange", onchange);
  // IE 9 and lower:
  else if ("onfocusin" in document)
    document.onfocusin = document.onfocusout = onchange;
  // All others:
  else
    window.onpageshow = window.onpagehide
    = window.onfocus = window.onblur = onchange;

  function onchange (evt) {
    var v = "visible", h = "hidden",
        evtMap = {
          focus:v, focusin:v, pageshow:v, blur:h, focusout:h, pagehide:h
        };

    evt = evt || window.event;
    if (evt.type in evtMap)
      document.body.className = evtMap[evt.type];
    else
      document.body.className = this[hidden] ? "hidden" : "visible";
  }

  // set the initial state (but only if browser supports the Page Visibility API)
  if( document[hidden] !== undefined )
    onchange({type: document[hidden] ? "blur" : "focus"});
})();

ie9及以下版本需要onfocusin和onfocusout,而所有其他都使用onfocus和onblur,除了iOS,它使用onpageshow和onpagehide。

稍微复杂一点的方法是使用setInterval()检查鼠标位置并与上次检查进行比较。如果鼠标在一段时间内没有移动,则用户可能处于空闲状态。

这有一个额外的好处,可以告诉用户是否空闲,而不仅仅是检查窗口是否处于活动状态。

正如许多人指出的那样,这并不总是一种检查用户或浏览器窗口是否空闲的好方法,因为用户甚至可能没有使用鼠标或正在观看视频或类似的内容。我只是建议一种检查空闲状态的方法。

这适用于所有现代浏览器:

更改制表符时 更改窗口时(Alt+Tab) 当从任务栏最大化另一个程序时

var eventName;
var visible = true;
var propName = "hidden";
if (propName in document) eventName = "visibilitychange";
else if ((propName = "msHidden") in document) eventName = "msvisibilitychange";
else if ((propName = "mozHidden") in document) eventName = "mozvisibilitychange";
else if ((propName = "webkitHidden") in document) eventName = "webkitvisibilitychange";
if (eventName) document.addEventListener(eventName, handleChange);

if ("onfocusin" in document) document.onfocusin = document.onfocusout = handleChange; //IE 9
window.onpageshow = window.onpagehide = window.onfocus = window.onblur = handleChange;// Changing tab with alt+tab

// Initialize state if Page Visibility API is supported
if (document[propName] !== undefined) handleChange({ type: document[propName] ? "blur" : "focus" });

function handleChange(evt) {
  evt = evt || window.event;
  if (visible && (["blur", "focusout", "pagehide"].includes(evt.type) || (this && this[propName]))){
    visible = false;
    console.log("Out...")
  }
  else if (!visible && (["focus", "focusin", "pageshow"].includes(evt.type) || (this && !this[propName]))){
    visible = true;
    console.log("In...")
  }
}

我重读了@daniel-buckmaster的版本 我没有做多次尝试,但是,代码对我来说似乎更优雅…

// on-visibility-change.js v1.0.1, based on https://stackoverflow.com/questions/1060008/is-there-a-way-to-detect-if-a-browser-window-is-not-currently-active#38710376
function onVisibilityChange(callback) {
    let d = document;
    let visible = true;
    let prefix;
    if ('hidden' in d) {
        prefix = 'h';
    } else if ('webkitHidden' in d) {
        prefix = 'webkitH';
    } else if ('mozHidden' in d) {
        prefix = 'mozH';
    } else if ('msHidden' in d) {
        prefix = 'msH';
    } else if ('onfocusin' in d) { // ie 9 and lower
        d.onfocusin = focused;
        d.onfocusout = unfocused;
    } else { // others
        window.onpageshow = window.onfocus = focused;
        window.onpagehide = window.onblur = unfocused;
    };
    if (prefix) {
        visible = !d[prefix + 'idden'];
        d.addEventListener(prefix.substring(0, prefix.length - 1) + 'visibilitychange', function() {
            (d[prefix + 'idden'] ? unfocused : focused)();
        });
    };

    function focused() {
        if (!visible) {
            callback(visible = true);
        };
    };

    function unfocused() {
        if (visible) {
            callback(visible = false);
        };
    };
};

这在chrome 67和firefox 67上都适用,

if(!document.hasFocus()) {
    // do stuff
}