首先在表中配置:

const routes: Routes = [  
{
  path: 'class/:id/enrollment/:guid',
  component: ClassEnrollmentComponent
 }
];

现在在类型脚本代码中:

this.router.navigate([`class/${classId}/enrollment/${4545455}`]);

接收另一个组件中的参数

 this.activatedRoute.params.subscribe(params => {
  let id = params['id'];
  let guid = params['guid'];

  console.log(`${id},${guid}`);
  });

首先在表中配置:

const routes: Routes = [  
{
  path: 'class/:id/enrollment/:guid',
  component: ClassEnrollmentComponent
 }
];

现在在类型脚本代码中:

this.router.navigate([`class/${classId}/enrollment/${4545455}`]);

接收另一个组件中的参数

 this.activatedRoute.params.subscribe(params => {
  let id = params['id'];
  let guid = params['guid'];

  console.log(`${id},${guid}`);
  });

也许这个回答有点晚，但是如果你想用param浏览另一个页面，

[routerLink]="['/user', user.id, 'details']"

此外，你不应该忘记路由配置，

 [path: 'user/:id/details', component:userComponent, pathMatch: 'full']

constructor(private activatedRoute: ActivatedRoute) {}

在你要用的箱子里

`this.activatedRoute.parmas.subscribe(params => { console.log(params['type']) }); }`

用params代替queryparamas从url -中获取参数

非常简单

<a routerLink="/user/{{id}}/details"></a>

有多种方法可以实现这一点。

通过[routerLink]指令 Router类的navigate(Array)方法 navigateByUrl(string)方法，它接受字符串并返回承诺

routerLink属性要求你将routingModule导入到特性模块中，以防你延迟加载了特性模块，或者如果app-routing-module没有自动添加到AppModule imports数组中，则直接导入。

RouterLink

<a [routerLink]="['/user', user.id]">John Doe</a>
<a routerLink="urlString">John Doe</a> // urlString is computed in your component

导航

// Inject Router into your component
// Inject ActivatedRoute into your component. This will allow the route to be done related to the current url
this._router.navigate(['user',user.id], {relativeTo: this._activatedRoute})

NavigateByUrl

this._router.navigateByUrl(urlString).then((bool) => {}).catch()