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2024-08-12 10:00:07

在PHP中转换时间戳到时间之前，例如1天前，2天前…

我正在尝试转换格式为2009-09-12 20:57:19的时间戳，并将其转换为3分钟前用PHP。

我找到了一个有用的脚本来做这件事，但我认为它正在寻找一种不同的格式来用作时间变量。我想修改的脚本与此格式的工作是:

function _ago($tm,$rcs = 0) {
    $cur_tm = time(); 
    $dif = $cur_tm-$tm;
    $pds = array('second','minute','hour','day','week','month','year','decade');
    $lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);

    for($v = sizeof($lngh)-1; ($v >= 0)&&(($no = $dif/$lngh[$v])<=1); $v--); if($v < 0) $v = 0; $_tm = $cur_tm-($dif%$lngh[$v]);
        $no = floor($no);
        if($no <> 1)
            $pds[$v] .='s';
        $x = sprintf("%d %s ",$no,$pds[$v]);
        if(($rcs == 1)&&($v >= 1)&&(($cur_tm-$_tm) > 0))
            $x .= time_ago($_tm);
        return $x;
    }

我认为在前几行脚本试图做的事情看起来像这样(不同的日期格式数学):

$dif = 1252809479 - 2009-09-12 20:57:19;

如何将我的时间戳转换成那种(unix?)格式?

当前回答

这是我的解决方案，请检查并根据您的要求修改

function getHowLongAgo($date, $display = array('Year', 'Month', 'Day', 'Hour', 'Minute', 'Second'), $ago = '') {
        date_default_timezone_set('Australia/Sydney');
        $timestamp = strtotime($date);
        $timestamp = (int) $timestamp;
        $current_time = time();
        $diff = $current_time - $timestamp;

        //intervals in seconds
        $intervals = array(
            'year' => 31556926, 'month' => 2629744, 'week' => 604800, 'day' => 86400, 'hour' => 3600, 'minute' => 60
        );

        //now we just find the difference
        if ($diff == 0) {
            return ' Just now ';
        }

        if ($diff < 60) {
            return $diff == 1 ? $diff . ' second ago ' : $diff . ' seconds ago ';
        }

        if ($diff >= 60 && $diff < $intervals['hour']) {
            $diff = floor($diff / $intervals['minute']);
            return $diff == 1 ? $diff . ' minute ago ' : $diff . ' minutes ago ';
        }

        if ($diff >= $intervals['hour'] && $diff < $intervals['day']) {
            $diff = floor($diff / $intervals['hour']);
            return $diff == 1 ? $diff . ' hour ago ' : $diff . ' hours ago ';
        }

        if ($diff >= $intervals['day'] && $diff < $intervals['week']) {
            $diff = floor($diff / $intervals['day']);
            return $diff == 1 ? $diff . ' day ago ' : $diff . ' days ago ';
        }

        if ($diff >= $intervals['week'] && $diff < $intervals['month']) {
            $diff = floor($diff / $intervals['week']);
            return $diff == 1 ? $diff . ' week ago ' : $diff . ' weeks ago ';
        }

        if ($diff >= $intervals['month'] && $diff < $intervals['year']) {
            $diff = floor($diff / $intervals['month']);
            return $diff == 1 ? $diff . ' month ago ' : $diff . ' months ago ';
        }

        if ($diff >= $intervals['year']) {
            $diff = floor($diff / $intervals['year']);
            return $diff == 1 ? $diff . ' year ago ' : $diff . ' years ago ';
        }
    }

谢谢

2014-10-09 13:08:43

其他回答

# This function prints the difference between two php datetime objects
# in a more human readable form
# inputs should be like strtotime($date)
function humanizeDateDiffference($now,$otherDate=null,$offset=null){
    if($otherDate != null){
        $offset = $now - $otherDate;
    }
    if($offset != null){
        $deltaS = $offset%60;
        $offset /= 60;
        $deltaM = $offset%60;
        $offset /= 60;
        $deltaH = $offset%24;
        $offset /= 24;
        $deltaD = ($offset > 1)?ceil($offset):$offset;      
    } else{
        throw new Exception("Must supply otherdate or offset (from now)");
    }
    if($deltaD > 1){
        if($deltaD > 365){
            $years = ceil($deltaD/365);
            if($years ==1){
                return "last year"; 
            } else{
                return "<br>$years years ago";
            }   
        }
        if($deltaD > 6){
            return date('d-M',strtotime("$deltaD days ago"));
        }       
        return "$deltaD days ago";
    }
    if($deltaD == 1){
        return "Yesterday";
    }
    if($deltaH == 1){
        return "last hour";
    }
    if($deltaM == 1){
        return "last minute";
    }
    if($deltaH > 0){
        return $deltaH." hours ago";
    }
    if($deltaM > 0){
        return $deltaM." minutes ago";
    }
    else{
        return "few seconds ago";
    }
}
2014-10-17 12:50:33

这是我的解决方案，请检查并根据您的要求修改

function getHowLongAgo($date, $display = array('Year', 'Month', 'Day', 'Hour', 'Minute', 'Second'), $ago = '') {
        date_default_timezone_set('Australia/Sydney');
        $timestamp = strtotime($date);
        $timestamp = (int) $timestamp;
        $current_time = time();
        $diff = $current_time - $timestamp;

        //intervals in seconds
        $intervals = array(
            'year' => 31556926, 'month' => 2629744, 'week' => 604800, 'day' => 86400, 'hour' => 3600, 'minute' => 60
        );

        //now we just find the difference
        if ($diff == 0) {
            return ' Just now ';
        }

        if ($diff < 60) {
            return $diff == 1 ? $diff . ' second ago ' : $diff . ' seconds ago ';
        }

        if ($diff >= 60 && $diff < $intervals['hour']) {
            $diff = floor($diff / $intervals['minute']);
            return $diff == 1 ? $diff . ' minute ago ' : $diff . ' minutes ago ';
        }

        if ($diff >= $intervals['hour'] && $diff < $intervals['day']) {
            $diff = floor($diff / $intervals['hour']);
            return $diff == 1 ? $diff . ' hour ago ' : $diff . ' hours ago ';
        }

        if ($diff >= $intervals['day'] && $diff < $intervals['week']) {
            $diff = floor($diff / $intervals['day']);
            return $diff == 1 ? $diff . ' day ago ' : $diff . ' days ago ';
        }

        if ($diff >= $intervals['week'] && $diff < $intervals['month']) {
            $diff = floor($diff / $intervals['week']);
            return $diff == 1 ? $diff . ' week ago ' : $diff . ' weeks ago ';
        }

        if ($diff >= $intervals['month'] && $diff < $intervals['year']) {
            $diff = floor($diff / $intervals['month']);
            return $diff == 1 ? $diff . ' month ago ' : $diff . ' months ago ';
        }

        if ($diff >= $intervals['year']) {
            $diff = floor($diff / $intervals['year']);
            return $diff == 1 ? $diff . ' year ago ' : $diff . ' years ago ';
        }
    }

谢谢

2014-10-09 13:08:43

我不知道为什么还没有人提到碳。

https://github.com/briannesbitt/Carbon

这实际上是php dateTime的扩展(这里已经使用了)，它有:diffForHumans方法。所以你所需要做的就是:

$dt = Carbon::parse('2012-9-5 23:26:11.123789');
echo $dt->diffForHumans();

更多例子:http://carbon.nesbot.com/docs/#api-humandiff

这个解决方案的优点:

它适用于未来的日期，并将在2个月等时间内返回。 你可以使用本地化来获取其他语言，多元化也很好 如果你开始用碳来做其他事情，处理日期就会变得非常容易。

2016-06-21 11:33:35

此函数不是为英语语言而设计的。我把这些单词翻译成英语。在用于英语之前，这需要更多的修正。

function ago($d) {
$ts = time() - strtotime(str_replace("-","/",$d));

        if($ts>315360000) $val = round($ts/31536000,0).' year';
        else if($ts>94608000) $val = round($ts/31536000,0).' years';
        else if($ts>63072000) $val = ' two years';
        else if($ts>31536000) $val = ' a year';

        else if($ts>24192000) $val = round($ts/2419200,0).' month';
        else if($ts>7257600) $val = round($ts/2419200,0).' months';
        else if($ts>4838400) $val = ' two months';
        else if($ts>2419200) $val = ' a month';


        else if($ts>6048000) $val = round($ts/604800,0).' week';
        else if($ts>1814400) $val = round($ts/604800,0).' weeks';
        else if($ts>1209600) $val = ' two weeks';
        else if($ts>604800) $val = ' a week';

        else if($ts>864000) $val = round($ts/86400,0).' day';
        else if($ts>259200) $val = round($ts/86400,0).' days';
        else if($ts>172800) $val = ' two days';
        else if($ts>86400) $val = ' a day';

        else if($ts>36000) $val = round($ts/3600,0).' year';
        else if($ts>10800) $val = round($ts/3600,0).' years';
        else if($ts>7200) $val = ' two years';
        else if($ts>3600) $val = ' a year';

        else if($ts>600) $val = round($ts/60,0).' minute';
        else if($ts>180) $val = round($ts/60,0).' minutes';
        else if($ts>120) $val = ' two minutes';
        else if($ts>60) $val = ' a minute';

        else if($ts>10) $val = round($ts,0).' second';
        else if($ts>2) $val = round($ts,0).' seconds';
        else if($ts>1) $val = ' two seconds';
        else $val = $ts.' a second';


        return $val;
    }
2014-12-16 20:27:34

我试过了，效果很好

$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-10');
$difference = $datetime1->diff($datetime2);
echo formatOutput($difference);

function formatOutput($diff){
    /* function to return the highrst defference fount */
    if(!is_object($diff)){
        return;
    }

    if($diff->y > 0){
        return $diff->y .(" year".($diff->y > 1?"s":"")." ago");
    }

    if($diff->m > 0){
        return $diff->m .(" month".($diff->m > 1?"s":"")." ago");
    }

    if($diff->d > 0){
        return $diff->d .(" day".($diff->d > 1?"s":"")." ago");
    }

    if($diff->h > 0){
        return $diff->h .(" hour".($diff->h > 1?"s":"")." ago");
    }

    if($diff->i > 0){
        return $diff->i .(" minute".($diff->i > 1?"s":"")." ago");
    }

    if($diff->s > 0){
        return $diff->s .(" second".($diff->s > 1?"s":"")." ago");
    }
}

在这里查看这个链接作为参考

谢谢!玩得开心。

2017-10-24 09:14:14

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