我正在尝试转换格式为2009-09-12 20:57:19的时间戳,并将其转换为3分钟前用PHP。

我找到了一个有用的脚本来做这件事,但我认为它正在寻找一种不同的格式来用作时间变量。我想修改的脚本与此格式的工作是:

function _ago($tm,$rcs = 0) {
    $cur_tm = time(); 
    $dif = $cur_tm-$tm;
    $pds = array('second','minute','hour','day','week','month','year','decade');
    $lngh = array(1,60,3600,86400,604800,2630880,31570560,315705600);

    for($v = sizeof($lngh)-1; ($v >= 0)&&(($no = $dif/$lngh[$v])<=1); $v--); if($v < 0) $v = 0; $_tm = $cur_tm-($dif%$lngh[$v]);
        $no = floor($no);
        if($no <> 1)
            $pds[$v] .='s';
        $x = sprintf("%d %s ",$no,$pds[$v]);
        if(($rcs == 1)&&($v >= 1)&&(($cur_tm-$_tm) > 0))
            $x .= time_ago($_tm);
        return $x;
    }

我认为在前几行脚本试图做的事情看起来像这样(不同的日期格式数学):

$dif = 1252809479 - 2009-09-12 20:57:19;

如何将我的时间戳转换成那种(unix?)格式?


当前回答

我做了这个,它工作得很好,它既适用于Unix时间戳,如1470919932,也适用于格式化时间,如16-08-11 14:53:30

function timeAgo($time_ago) {
    $time_ago =  strtotime($time_ago) ? strtotime($time_ago) : $time_ago;
    $time  = time() - $time_ago;

switch($time):
// seconds
case $time <= 60;
return 'lessthan a minute ago';
// minutes
case $time >= 60 && $time < 3600;
return (round($time/60) == 1) ? 'a minute' : round($time/60).' minutes ago';
// hours
case $time >= 3600 && $time < 86400;
return (round($time/3600) == 1) ? 'a hour ago' : round($time/3600).' hours ago';
// days
case $time >= 86400 && $time < 604800;
return (round($time/86400) == 1) ? 'a day ago' : round($time/86400).' days ago';
// weeks
case $time >= 604800 && $time < 2600640;
return (round($time/604800) == 1) ? 'a week ago' : round($time/604800).' weeks ago';
// months
case $time >= 2600640 && $time < 31207680;
return (round($time/2600640) == 1) ? 'a month ago' : round($time/2600640).' months ago';
// years
case $time >= 31207680;
return (round($time/31207680) == 1) ? 'a year ago' : round($time/31207680).' years ago' ;

endswitch;
}

?>

其他回答

function time_elapsed_string($ptime)
{
    $etime = time() - $ptime;

    if ($etime < 1)
    {
        return '0 seconds';
    }

    $a = array( 365 * 24 * 60 * 60  =>  'year',
                 30 * 24 * 60 * 60  =>  'month',
                      24 * 60 * 60  =>  'day',
                           60 * 60  =>  'hour',
                                60  =>  'minute',
                                 1  =>  'second'
                );
    $a_plural = array( 'year'   => 'years',
                       'month'  => 'months',
                       'day'    => 'days',
                       'hour'   => 'hours',
                       'minute' => 'minutes',
                       'second' => 'seconds'
                );

    foreach ($a as $secs => $str)
    {
        $d = $etime / $secs;
        if ($d >= 1)
        {
            $r = round($d);
            return $r . ' ' . ($r > 1 ? $a_plural[$str] : $str) . ' ago';
        }
    }
}
$time_elapsed = timeAgo($time_ago); //The argument $time_ago is in timestamp (Y-m-d H:i:s)format.

//Function definition

function timeAgo($time_ago)
{
    $time_ago = strtotime($time_ago);
    $cur_time   = time();
    $time_elapsed   = $cur_time - $time_ago;
    $seconds    = $time_elapsed ;
    $minutes    = round($time_elapsed / 60 );
    $hours      = round($time_elapsed / 3600);
    $days       = round($time_elapsed / 86400 );
    $weeks      = round($time_elapsed / 604800);
    $months     = round($time_elapsed / 2600640 );
    $years      = round($time_elapsed / 31207680 );
    // Seconds
    if($seconds <= 60){
        return "just now";
    }
    //Minutes
    else if($minutes <=60){
        if($minutes==1){
            return "one minute ago";
        }
        else{
            return "$minutes minutes ago";
        }
    }
    //Hours
    else if($hours <=24){
        if($hours==1){
            return "an hour ago";
        }else{
            return "$hours hrs ago";
        }
    }
    //Days
    else if($days <= 7){
        if($days==1){
            return "yesterday";
        }else{
            return "$days days ago";
        }
    }
    //Weeks
    else if($weeks <= 4.3){
        if($weeks==1){
            return "a week ago";
        }else{
            return "$weeks weeks ago";
        }
    }
    //Months
    else if($months <=12){
        if($months==1){
            return "a month ago";
        }else{
            return "$months months ago";
        }
    }
    //Years
    else{
        if($years==1){
            return "one year ago";
        }else{
            return "$years years ago";
        }
    }
}

我试过了,效果很好

$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-10');
$difference = $datetime1->diff($datetime2);
echo formatOutput($difference);

function formatOutput($diff){
    /* function to return the highrst defference fount */
    if(!is_object($diff)){
        return;
    }

    if($diff->y > 0){
        return $diff->y .(" year".($diff->y > 1?"s":"")." ago");
    }

    if($diff->m > 0){
        return $diff->m .(" month".($diff->m > 1?"s":"")." ago");
    }

    if($diff->d > 0){
        return $diff->d .(" day".($diff->d > 1?"s":"")." ago");
    }

    if($diff->h > 0){
        return $diff->h .(" hour".($diff->h > 1?"s":"")." ago");
    }

    if($diff->i > 0){
        return $diff->i .(" minute".($diff->i > 1?"s":"")." ago");
    }

    if($diff->s > 0){
        return $diff->s .(" second".($diff->s > 1?"s":"")." ago");
    }
}

在这里查看这个链接作为参考

谢谢!玩得开心。

它能帮你检查

   function calculate_time_span($seconds)
{  
 $year = floor($seconds /31556926);
$months = floor($seconds /2629743);
$week=floor($seconds /604800);
$day = floor($seconds /86400); 
$hours = floor($seconds / 3600);
 $mins = floor(($seconds - ($hours*3600)) / 60); 
$secs = floor($seconds % 60);
 if($seconds < 60) $time = $secs." seconds ago";
 else if($seconds < 3600 ) $time =($mins==1)?$mins."now":$mins." mins ago";
 else if($seconds < 86400) $time = ($hours==1)?$hours." hour ago":$hours." hours ago";
 else if($seconds < 604800) $time = ($day==1)?$day." day ago":$day." days ago";
 else if($seconds < 2629743) $time = ($week==1)?$week." week ago":$week." weeks ago";
 else if($seconds < 31556926) $time =($months==1)? $months." month ago":$months." months ago";
 else $time = ($year==1)? $year." year ago":$year." years ago";
return $time; 
}  
  $seconds = time() - strtotime($post->post_date); 
echo calculate_time_span($seconds); 

您必须将时间戳的每一部分都转换为Unix时间。例如时间戳:2009-09-12 20:57:19。

((2008-1970)*365)+(8*30)+12)*24+20可以大致估算出自1970年1月1日以来的工作时间。

用这个数字乘以60,再加57,就得到了分钟数。

用这个,乘以60,再加19。

这将非常粗略和不准确地转换它。

有什么原因让你不能开始使用正常的Unix时间吗?