方便的俏皮话

for D in *; do echo "$D"; done
for D in *; do find "$D" -type d; done ### Option A

find * -type d ### Option B

选项A适用于中间有空格的文件夹。而且，通常更快，因为它不会将文件夹名称中的每个单词作为单独的实体打印。

# Option A
$ time for D in ./big_dir/*; do find "$D" -type d > /dev/null; done
real    0m0.327s
user    0m0.084s
sys     0m0.236s

# Option B
$ time for D in `find ./big_dir/* -type d`; do echo "$D" > /dev/null; done
real    0m0.787s
user    0m0.484s
sys     0m0.308s

for D in `find . -type d`
do
    //Do whatever you need with D
done

如果你想在文件夹内而不是在文件夹上执行操作。

说明:您有许多pdf文件，希望将它们集中在一个文件夹中。 我的文件夹

   AV 001/
   AV 002/

for D in *; do cd "$D"; # VERY DANGEROUS COMMAND - DONT USE #-- missing "", it will list files too. It can go up too. for d in */; do cd "$d"; echo $d; cd ..; done; # works succesfully for D in "$(ls -d */)"; do cd "$D"; done; # bash: cd: $'Athens Voice 001/\nAthens Voice 002/' - there is no such folder for D in "$(*/)"; do cd "$D"; done; # bash: Athens Voice 001/: is folder for D in "$(`find . -type d`)"; do cd $D; done; # bash: ./Athens: there is no such folder or file for D in *; do if [ -d "${D}" ] then cd ${D}; done; # many arguments

最简单的非递归方法是:

for d in */; do
    echo "$d"
done

末尾的/表示只使用目录。

没有必要

找到 呜 ...

找到。-type d -print0 | xargs -0 -n 1 my_command

这将创建一个子shell(这意味着当while循环退出时，变量值将丢失):

find . -type d | while read -r dir
do
    something
done

这不会:

while read -r dir
do
    something
done < <(find . -type d)

如果目录名中有空格，这两种方法都可以工作。