我想捕捉下面文本框上的回车键事件。为了更清楚地说明这一点,我使用ng-repeat填充tbody。下面是HTML:

<td><input type="number" id="closeqty{{$index}}" class="pagination-right closefield" 
    data-ng-model="closeqtymodel" data-ng-change="change($index)" required placeholder="{{item.closeMeasure}}" /></td>

这是我的模块:

angular.module('components', ['ngResource']);

我使用一个资源来填充表,我的控制器代码是:

function Ajaxy($scope, $resource) {
//controller which has resource to populate the table 
}

当前回答

<!DOCTYPE html>
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<body>
<div ng-app="myApp" ng-controller="myCtrl">
Informe your name:<input type="text" ng-model="pergunta" ng-keypress="pressionou_enter($event)" ></input> 
<button ng-click="chamar()">submit</button>
<h1>{{resposta}}</h1> 
</div>
<script>
var app = angular.module('myApp', []);
//create a service mitsuplik
app.service('mitsuplik', function() {
    this.myFunc = function (parametro) {
        var tmp = ""; 
        for (var x=0;x<parametro.length;x++)
            {
            tmp = parametro.substring(x,x+1) + tmp;
            } 
        return tmp;
    }
});
//Calling our service
app.controller('myCtrl', function($scope, mitsuplik) { 
  $scope.chamar = function() { 
        $scope.resposta = mitsuplik.myFunc($scope.pergunta); 
    };
  //if mitsuplik press [ENTER], execute too
  $scope.pressionou_enter = function(keyEvent) {
             if (keyEvent.which === 13) 
                { 
                $scope.chamar();
                }

    }
});
</script>
</body>
</html>

其他回答

这是我在开发一个有类似需求的应用程序时得出的结论, 它不需要写一个指令,它是相对简单的告诉它做什么:

<input type="text" ng-keypress="($event.charCode==13)?myFunction():return" placeholder="Will Submit on Enter">

你可以使用ng-keydown ="myFunction($event)"作为属性。

<input ng-keydown="myFunction($event)" type="number">

myFunction(event) {
    if(event.keyCode == 13) {   // '13' is the key code for enter
        // do what you want to do when 'enter' is pressed :)
    }
}

所有你需要做的事情是获得事件如下:

console.log(angular.element(event.which));

指令可以做到这一点,但你不能这样做。

这是我的指示:

mainApp.directive('number', function () {
    return {
        link: function (scope, el, attr) {
            el.bind("keydown keypress", function (event) {
                //ignore all characters that are not numbers, except backspace, delete, left arrow and right arrow
                if ((event.keyCode < 48 || event.keyCode > 57) && event.keyCode != 8 && event.keyCode != 46 && event.keyCode != 37 && event.keyCode != 39) {
                    event.preventDefault();
                }
            });
        }
    };
});

用法:

<input number />
<!DOCTYPE html>
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<body>
<div ng-app="myApp" ng-controller="myCtrl">
Informe your name:<input type="text" ng-model="pergunta" ng-keypress="pressionou_enter($event)" ></input> 
<button ng-click="chamar()">submit</button>
<h1>{{resposta}}</h1> 
</div>
<script>
var app = angular.module('myApp', []);
//create a service mitsuplik
app.service('mitsuplik', function() {
    this.myFunc = function (parametro) {
        var tmp = ""; 
        for (var x=0;x<parametro.length;x++)
            {
            tmp = parametro.substring(x,x+1) + tmp;
            } 
        return tmp;
    }
});
//Calling our service
app.controller('myCtrl', function($scope, mitsuplik) { 
  $scope.chamar = function() { 
        $scope.resposta = mitsuplik.myFunc($scope.pergunta); 
    };
  //if mitsuplik press [ENTER], execute too
  $scope.pressionou_enter = function(keyEvent) {
             if (keyEvent.which === 13) 
                { 
                $scope.chamar();
                }

    }
});
</script>
</body>
</html>