试一试，对我有用:

var today = new Date();
var yesterday = new Date(today.setDate(today.getDate() - 1)); `

这让我得到了一个日期对象回来为昨天

我想要这样的答案:

const yesterday = d => new Date(d.setDate(d.getDate() - 1));

问题是它突变了d，所以让我们把突变藏在里面。

const yesterday = (date) => {
  const dateCopy = new Date(date);
  return new Date(dateCopy.setDate(dateCopy.getDate() - 1));
}

我们可以将其分解为一行表达式，但它变得有点难以阅读:

const yesterday = d => new Date(new Date(d).setDate(d.getDate() - 1));

我将其扩展为addDays和addMonths函数:

/** * Add (or subtract) days from a date * * @param {Number} days * @returns {Function} Date => Date + days */ const addDays = (days) => (date) => new Date(new Date(date).setDate(date.getDate() + days)); /** * Add (or subtract) months from a date * * @param {Number} months * @returns {Function} Date => Date + months */ const addMonths = (months) => (date) => new Date(new Date(date).setMonth(date.getMonth() + months)); // We can recreate the yesterday function: const yesterday = addDays(-1) // note that `now` doesn't get mutated const now = new Date(); console.log({ now, yesterday: yesterday(now) }) const lastMonth = addMonths(-1)(now); console.log({ now, lastMonth }) .as-console-wrapper { max-height: 100% !important; }

但在这一点上，你可能想开始使用date-fns addDays。

d.setHours(0,0,0,0);

会成功的

试试这个

var d = new Date();
d.setDate(d.getDate() - 1);

我使用矩库，它非常灵活，易于使用。

在你的情况下:

let yesterday = moment().subtract(1, 'day').toDate();

var date = new Date();

date ; //# => Fri Apr 01 2011 11:14:50 GMT+0200 (CEST)

date.setDate(date.getDate() - 1);

date ; //# => Thu Mar 31 2011 11:14:50 GMT+0200 (CEST)