如何检查给定的字符串是否是有效的URL地址?

我对正则表达式的知识是基本的,不允许我从我已经在网上看到的数百个正则表达式中进行选择。


当前回答

下面的正则表达式适用于我:

(http(s)?:\/\/.)?(ftp(s)?:\/\/.)?(www\.)?[-a-zA-Z0-9@:%._\+~#=]{0,256}\.[a-z] 
{2,6}\b([-a-zA-Z0-9@:%_\+.~#?&//=]*)

匹配:

https://google.com t.me https://t.me ftp://google.com http://sm.tj http://bro.tj t.me/rshss https:google.com www.cool.com.au http://www.cool.com.au http://www.cool.com.au/ersdfs http://www.cool.com.au/ersdfs?dfd=dfgd@s=1 http://www.cool.com:81/index.html

其他回答

function validateURL(textval) {
            var urlregex = new RegExp(
            "^(http|https|ftp)\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(:[a-zA-Z0-9]*)?/?([a-zA-Z0-9\-\._\?\,\'/\\\+&%\$#\=~])*$");
            return urlregex.test(textval);
        }

匹配 http://www.asdah.com/~joe | ftp://ftp.asdah.co.uk:2828/asdah%20asdah.gif | https://asdah.gov/asdh-ah.as

下面的表达式将适用于所有流行域。它将接受以下网址:

www.yourwebsite.com http://www.yourwebsite.com www.yourwebsite.com yourwebsite.com yourwebsite.co.in

此外,它将使消息与url作为链接也 例如,请访问你的网站 在上面的例子中,它将使yourwebsite.com作为超链接

if (new RegExp("([-a-z0-9]{1,63}\\.)*?[a-z0-9][-a-z0-9]{0,61}[a-z0-9]\\.(com|com/|org|gov|cm|net|online|live|biz|us|uk|co.us|co.uk|in|co.in|int|info|edu|mil|ca|co|co.au|org/|gov/|cm/|net/|online/|live/|biz/|us/|uk/|co.us/|co.uk/|in/|co.in/|int/|info/|edu/|mil/|ca/|co/|co.au/)(/[-\\w@\\+\\.~#\\?*&/=% ]*)?$").test(strMessage) || (new RegExp("^[a-z ]+[\.]?[a-z ]+?[\.]+[a-z ]+?[\.]+[a-z ]+?[-\\w@\\+\\.~#\\?*&/=% ]*").test(strMessage) && new RegExp("([a-zA-Z0-9]+://)?([a-zA-Z0-9_]+:[a-zA-Z0-9_]+@)?([a-zA-Z0-9.-]+\\.[A-Za-z]{2,4})(:[0-9]+)?(/.*)?").test(strMessage)) || (new RegExp("^[a-z ]+[\.]?[a-z ]+?[-\\w@\\+\\.~#\\?*&/=% ]*").test(strMessage) && new RegExp("([a-zA-Z0-9]+://)?([a-zA-Z0-9_]+:[a-zA-Z0-9_]+@)?([a-zA-Z0-9.-]+\\.[A-Za-z]{2,4})(:[0-9]+)?(/.*)?").test(strMessage))) {
  if (new RegExp("^[a-z ]+[\.]?[a-z ]+?[\.]+[a-z ]+?[\.]+[a-z ]+?$").test(strMessage) && new RegExp("([a-zA-Z0-9]+://)?([a-zA-Z0-9_]+:[a-zA-Z0-9_]+@)?([a-zA-Z0-9.-]+\\.[A-Za-z]{2,4})(:[0-9]+)?(/.*)?").test(strMessage)) {
    var url1 = /(^|<|\s)([\w\.]+\.(?:com|org|gov|cm|net|online|live|biz|us|uk|co.us|co.uk|in|co.in|int|info|edu|mil|ca|co|co.au))(\s|>|$)/g;
    var html = $.trim(strMessage);
    if (html) {
      html = html.replace(url1, '$1<a style="color:blue; text-decoration:underline;" target="_blank"  href="http://$2">$2</a>$3');
    }
    returnString = html;
    return returnString;
  } else {
    var url1 = /(^|&lt;|\s)(www\..+?\.(?:com|org|gov|cm|net|online|live|biz|us|uk|co.us|co.uk|in|co.in|int|info|edu|mil|ca|co|co.au)[^,\s]*)(\s|&gt;|$)/g,
      url2 = /(^|&lt;|\s)(((https?|ftp):\/\/|mailto:).+?\.(?:com|org|gov|cm|net|online|live|biz|us|uk|co.us|co.uk|in|co.in|int|info|edu|mil|ca|co|co.au)[^,\s]*)(\s|&gt;|$)/g,
      url3 = /(^|&lt;|\s)([\w\.]+\.(?:com|org|gov|cm|net|online|live|biz|us|uk|co.us|co.uk|in|co.in|int|info|edu|mil|ca|co|co.au)[^,\s]*)(\s|&gt;|$)/g;

    var html = $.trim(strMessage);
    if (html) {
      html = html.replace(url1, '$1<a style="color:blue; text-decoration:underline;" target="_blank"  href="http://$2">$2</a>$3').replace(url2, '$1<a style="color:blue; text-decoration:underline;" target="_blank"  href="$2">$2</a>$5').replace(url3, '$1<a style="color:blue; text-decoration:underline;" target="_blank"  href="http://$2">$2</a>$3');
    }
    returnString = html;

    return returnString;
  }
}

非验证uri引用解析器

为了便于参考,这里是IETF规范:(TXT | HTML)。特别地,附录b用正则表达式解析URI引用演示了如何解析有效的正则表达式。这被描述为,

这是一个非验证URI引用解析器的例子,它将接受任何给定的字符串并提取URI组件。

下面是它们提供的正则表达式:

 ^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?

正如其他人所说,最好将此留给您已经在使用的库/框架。

我试着制定我的url版本。我的需求是在一个字符串中捕获实例,其中可能的url可以是cse.uom.ac.mu -注意它的前面没有http或www

String regularExpression = "((((ht{2}ps?://)?)((w{3}\\.)?))?)[^.&&[a-zA-Z0-9]][a-zA-Z0-9.-]+[^.&&[a-zA-Z0-9]](\\.[a-zA-Z]{2,3})";

assertTrue("www.google.com".matches(regularExpression));
assertTrue("www.google.co.uk".matches(regularExpression));
assertTrue("http://www.google.com".matches(regularExpression));
assertTrue("http://www.google.co.uk".matches(regularExpression));
assertTrue("https://www.google.com".matches(regularExpression));
assertTrue("https://www.google.co.uk".matches(regularExpression));
assertTrue("google.com".matches(regularExpression));
assertTrue("google.co.uk".matches(regularExpression));
assertTrue("google.mu".matches(regularExpression));
assertTrue("mes.intnet.mu".matches(regularExpression));
assertTrue("cse.uom.ac.mu".matches(regularExpression));

//cannot contain 2 '.' after www
assertFalse("www..dr.google".matches(regularExpression));

//cannot contain 2 '.' just before com
assertFalse("www.dr.google..com".matches(regularExpression));

// to test case where url www must be followed with a '.'
assertFalse("www:google.com".matches(regularExpression));

// to test case where url www must be followed with a '.'
//assertFalse("http://wwwe.google.com".matches(regularExpression));

// to test case where www must be preceded with a '.'
assertFalse("https://www@.google.com".matches(regularExpression));

一个简单的URL检查是

^(ftp|http|https):\/\/[^ "]+$