该SQL查询适用于大多数PostgreSQL版本，非常简单。

select table_name from information_schema.tables where table_schema='public' ;

从psql命令行界面，

首先，选择数据库

\c database_name

然后，这将显示当前模式中的所有表：

\dt

编程（当然也可以从psql接口）：

SELECT * FROM pg_catalog.pg_tables;

系统表位于pg_catalog数据库中。

\dt（不需要*）--将列出您已连接到的现有数据库的所有表。还需要注意：

\d[table_name]--将显示给定表的所有列，包括类型信息、引用和键约束。

运行带有-E标志的psql将响应内部用于实现的查询\dt和类似：

sudo -u postgres psql -E

postgres=# \dt       
********* QUERY **********
SELECT n.nspname as "Schema",
c.relname as "Name", 
CASE c.relkind WHEN 'r' THEN 'table' WHEN 'v' THEN 'view' WHEN 'i' THEN 'index' WHEN 'S' THEN 'sequence' WHEN 's' THEN 'special' END as "Type",
pg_catalog.pg_get_userbyid(c.relowner) as "Owner"
FROM pg_catalog.pg_class c
    LEFT JOIN pg_catalog.pg_namespace n ON n.oid = c.relnamespace
WHERE c.relkind IN ('r','')
    AND n.nspname <> 'pg_catalog'
    AND n.nspname <> 'information_schema'
    AND n.nspname !~ '^pg_toast'
AND pg_catalog.pg_table_is_visible(c.oid)
ORDER BY 1,2;        
**************************

使用psql:\dt

Or:

SELECT c.relname AS Tables_in FROM pg_catalog.pg_class c
        LEFT JOIN pg_catalog.pg_namespace n ON n.oid = c.relnamespace
WHERE pg_catalog.pg_table_is_visible(c.oid)
        AND c.relkind = 'r'
        AND relname NOT LIKE 'pg_%'
ORDER BY 1

作为一个快速的oneliner

# just list all the postgres tables sorted in the terminal
db='my_db_name'
clear;psql -d $db -t -c '\dt'|cut -c 11-|perl -ne 's/^([a-z_0-9]*)( )(.*)/$1/; print'

或者如果您更喜欢更清晰的json输出多行：

IFS='' read -r -d '' sql_code <<"EOF_CODE"
    select array_to_json(array_agg(row_to_json(t))) from (
        SELECT table_catalog,table_schema,table_name 
        FROM information_schema.tables
        ORDER BY table_schema,table_name ) t
EOF_CODE
psql -d postgres -t -q -c "$sql_code"|jq