我写了一个Python脚本,检查一个特定的电子邮件地址,并将新的电子邮件传递给一个外部程序。如何让这个脚本全天候执行,比如在Linux中将其转换为守护进程或服务。我是否还需要一个在程序中永不结束的循环,或者可以通过多次重新执行代码来完成?
当前回答
你应该使用python-daemon库,它会处理所有的事情。
从PyPI:库实现一个行为良好的Unix守护进程。
其他回答
你可以使用fork()将你的脚本从tty中分离出来,并让它继续运行,如下所示:
import os, sys
fpid = os.fork()
if fpid!=0:
# Running as daemon now. PID is fpid
sys.exit(0)
当然你还需要实现一个无限循环,比如
while 1:
do_your_check()
sleep(5)
希望这能让你开始。
您还可以使用shell脚本使python脚本作为服务运行。首先创建一个shell脚本,像这样运行python脚本(scriptname任意名称)
#!/bin/sh
script='/home/.. full path to script'
/usr/bin/python $script &
现在在/etc/init.d/scriptname中创建一个文件
#! /bin/sh
PATH=/bin:/usr/bin:/sbin:/usr/sbin
DAEMON=/home/.. path to shell script scriptname created to run python script
PIDFILE=/var/run/scriptname.pid
test -x $DAEMON || exit 0
. /lib/lsb/init-functions
case "$1" in
start)
log_daemon_msg "Starting feedparser"
start_daemon -p $PIDFILE $DAEMON
log_end_msg $?
;;
stop)
log_daemon_msg "Stopping feedparser"
killproc -p $PIDFILE $DAEMON
PID=`ps x |grep feed | head -1 | awk '{print $1}'`
kill -9 $PID
log_end_msg $?
;;
force-reload|restart)
$0 stop
$0 start
;;
status)
status_of_proc -p $PIDFILE $DAEMON atd && exit 0 || exit $?
;;
*)
echo "Usage: /etc/init.d/atd {start|stop|restart|force-reload|status}"
exit 1
;;
esac
exit 0
现在可以使用/etc/init.命令启动和停止python脚本D /scriptname start or stop。
假设您真的希望您的循环作为后台服务全天候运行
对于一个不需要向代码中注入库的解决方案,你可以简单地创建一个服务模板,因为你使用的是linux:
[Unit]
Description = <Your service description here>
After = network.target # Assuming you want to start after network interfaces are made available
[Service]
Type = simple
ExecStart = python <Path of the script you want to run>
User = # User to run the script as
Group = # Group to run the script as
Restart = on-failure # Restart when there are errors
SyslogIdentifier = <Name of logs for the service>
RestartSec = 5
TimeoutStartSec = infinity
[Install]
WantedBy = multi-user.target # Make it accessible to other users
将该文件放在您的守护进程服务文件夹(通常是/etc/systemd/system/)中,*. .使用以下systemctl命令安装它(可能需要sudo权限):
systemctl enable <service file name without .service extension>
systemctl daemon-reload
systemctl start <service file name without .service extension>
然后你可以使用命令检查你的服务是否在运行:
systemctl | grep running
这是一个很好的类,从这里采取:
#!/usr/bin/env python
import sys, os, time, atexit
from signal import SIGTERM
class Daemon:
"""
A generic daemon class.
Usage: subclass the Daemon class and override the run() method
"""
def __init__(self, pidfile, stdin='/dev/null', stdout='/dev/null', stderr='/dev/null'):
self.stdin = stdin
self.stdout = stdout
self.stderr = stderr
self.pidfile = pidfile
def daemonize(self):
"""
do the UNIX double-fork magic, see Stevens' "Advanced
Programming in the UNIX Environment" for details (ISBN 0201563177)
http://www.erlenstar.demon.co.uk/unix/faq_2.html#SEC16
"""
try:
pid = os.fork()
if pid > 0:
# exit first parent
sys.exit(0)
except OSError, e:
sys.stderr.write("fork #1 failed: %d (%s)\n" % (e.errno, e.strerror))
sys.exit(1)
# decouple from parent environment
os.chdir("/")
os.setsid()
os.umask(0)
# do second fork
try:
pid = os.fork()
if pid > 0:
# exit from second parent
sys.exit(0)
except OSError, e:
sys.stderr.write("fork #2 failed: %d (%s)\n" % (e.errno, e.strerror))
sys.exit(1)
# redirect standard file descriptors
sys.stdout.flush()
sys.stderr.flush()
si = file(self.stdin, 'r')
so = file(self.stdout, 'a+')
se = file(self.stderr, 'a+', 0)
os.dup2(si.fileno(), sys.stdin.fileno())
os.dup2(so.fileno(), sys.stdout.fileno())
os.dup2(se.fileno(), sys.stderr.fileno())
# write pidfile
atexit.register(self.delpid)
pid = str(os.getpid())
file(self.pidfile,'w+').write("%s\n" % pid)
def delpid(self):
os.remove(self.pidfile)
def start(self):
"""
Start the daemon
"""
# Check for a pidfile to see if the daemon already runs
try:
pf = file(self.pidfile,'r')
pid = int(pf.read().strip())
pf.close()
except IOError:
pid = None
if pid:
message = "pidfile %s already exist. Daemon already running?\n"
sys.stderr.write(message % self.pidfile)
sys.exit(1)
# Start the daemon
self.daemonize()
self.run()
def stop(self):
"""
Stop the daemon
"""
# Get the pid from the pidfile
try:
pf = file(self.pidfile,'r')
pid = int(pf.read().strip())
pf.close()
except IOError:
pid = None
if not pid:
message = "pidfile %s does not exist. Daemon not running?\n"
sys.stderr.write(message % self.pidfile)
return # not an error in a restart
# Try killing the daemon process
try:
while 1:
os.kill(pid, SIGTERM)
time.sleep(0.1)
except OSError, err:
err = str(err)
if err.find("No such process") > 0:
if os.path.exists(self.pidfile):
os.remove(self.pidfile)
else:
print str(err)
sys.exit(1)
def restart(self):
"""
Restart the daemon
"""
self.stop()
self.start()
def run(self):
"""
You should override this method when you subclass Daemon. It will be called after the process has been
daemonized by start() or restart().
"""
我推荐这个解决方案。您需要继承和重写方法运行。
import sys
import os
from signal import SIGTERM
from abc import ABCMeta, abstractmethod
class Daemon(object):
__metaclass__ = ABCMeta
def __init__(self, pidfile):
self._pidfile = pidfile
@abstractmethod
def run(self):
pass
def _daemonize(self):
# decouple threads
pid = os.fork()
# stop first thread
if pid > 0:
sys.exit(0)
# write pid into a pidfile
with open(self._pidfile, 'w') as f:
print >> f, os.getpid()
def start(self):
# if daemon is started throw an error
if os.path.exists(self._pidfile):
raise Exception("Daemon is already started")
# create and switch to daemon thread
self._daemonize()
# run the body of the daemon
self.run()
def stop(self):
# check the pidfile existing
if os.path.exists(self._pidfile):
# read pid from the file
with open(self._pidfile, 'r') as f:
pid = int(f.read().strip())
# remove the pidfile
os.remove(self._pidfile)
# kill daemon
os.kill(pid, SIGTERM)
else:
raise Exception("Daemon is not started")
def restart(self):
self.stop()
self.start()
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