因为这个问题已经被回答了,我只是想指出在JavaScript中获取对象构造函数的方法的差异。
构造函数和实际的对象/类名之间存在差异。如果下面的情况增加了您决策的复杂性,那么可能您正在寻找instanceof。或者你应该问问自己“我为什么要这样做?”这真的是我要解决的问题吗?”
注:
obj.constructor.name在旧的浏览器上不可用。
匹配(\w+)应该满足ES6样式类。
代码:
var what = function(obj) {
return obj.toString().match(/ (\w+)/)[1];
};
var p;
// Normal obj with constructor.
function Entity() {}
p = new Entity();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));
// Obj with prototype overriden.
function Player() { console.warn('Player constructor called.'); }
Player.prototype = new Entity();
p = new Player();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// Obj with constructor property overriden.
function OtherPlayer() { console.warn('OtherPlayer constructor called.'); }
OtherPlayer.constructor = new Player();
p = new OtherPlayer();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// Anonymous function obj.
p = new Function("");
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// No constructor here.
p = {};
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// ES6 class.
class NPC {
constructor() {
}
}
p = new NPC();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));
// ES6 class extended
class Boss extends NPC {
constructor() {
super();
}
}
p = new Boss();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));
结果:
代码:https://jsbin.com/wikiji/edit?js,控制台