是否有任何解决方案来获得一个对象的函数名?
function alertClassOrObject (o) {
window.alert(o.objectName); //"myObj" OR "myClass" as a String
}
function myClass () {
this.foo = function () {
alertClassOrObject(this);
}
}
var myObj = new myClass();
myObj.foo();
对于(var k in this){…} -没有关于className或ObjectName的信息。有可能弄到一个吗?
当前回答
我们需要的是:
在函数中封装一个常量(函数的名称等于我们想要获取的对象的名称) 在对象中使用箭头函数
console.clear (); function App(){//我的常量的名字是App 返回{ 答:{ b: { C:()=>{//这里很重要，使用箭头函数 console.log (this.constructor.name) ｝ ｝ ｝ ｝ ｝ const obj = new App();/ /使用 obj.a.b.c ();/ /应用程序 //使用react道具等 //例如，我们想把这个回调函数传递给某个组件 const myComponent = {}; myComponent。customProps = obj.a.b.c; myComponent.customProps ();/ /应用程序
其他回答
例子:
function Foo () { console.log('Foo function'); } var f = new Foo(); console.log('f', f.constructor.name); // -> "Foo" var Bar = function () { console.log('Anonymous function (as Bar)'); }; var b = new Bar(); console.log('b', b.constructor.name); // -> "Bar" var Abc = function Xyz() { console.log('Xyz function (as Abc)'); }; var a = new Abc(); console.log('a', a.constructor.name); // -> "Xyz" class Clazz { constructor() { console.log('Clazz class'); } } var c = new Clazz(); console.log('c', c.constructor.name); // -> "Clazz" var otherClass = class Cla2 { constructor() { console.log('Cla2 class (as otherClass)'); } } var c2 = new otherClass(); console.log('c2', c2.constructor.name); // -> "Cla2"
试试这个:
var classname = ("" + obj.constructor).split("function ")[1].split("(")[0];
因为这个问题已经被回答了，我只是想指出在JavaScript中获取对象构造函数的方法的差异。 构造函数和实际的对象/类名之间存在差异。如果下面的情况增加了您决策的复杂性，那么可能您正在寻找instanceof。或者你应该问问自己“我为什么要这样做?”这真的是我要解决的问题吗?”
注:
obj.constructor.name在旧的浏览器上不可用。 匹配(\w+)应该满足ES6样式类。
代码:
var what = function(obj) {
return obj.toString().match(/ (\w+)/)[1];
};
var p;
// Normal obj with constructor.
function Entity() {}
p = new Entity();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));
// Obj with prototype overriden.
function Player() { console.warn('Player constructor called.'); }
Player.prototype = new Entity();
p = new Player();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// Obj with constructor property overriden.
function OtherPlayer() { console.warn('OtherPlayer constructor called.'); }
OtherPlayer.constructor = new Player();
p = new OtherPlayer();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// Anonymous function obj.
p = new Function("");
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// No constructor here.
p = {};
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));
// ES6 class.
class NPC {
constructor() {
}
}
p = new NPC();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));
// ES6 class extended
class Boss extends NPC {
constructor() {
super();
}
}
p = new Boss();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));
结果:
代码:https://jsbin.com/wikiji/edit?js,控制台
在运行时获得类名的最有效方法
let className = this.constructor.name
获取对象的构造函数，然后检查它的name属性。
myObj.constructor.name
myClass”了。
