我想要这样的东西:
public class Stream
{
public startTime;
public endTime;
public getDuration()
{
return startTime - endTime;
}
}
同样重要的是，例如，如果startTime是23:00,endTime是1:00，则持续时间为2:00。
为了在Java中实现这一点，应该使用哪些类型?
当前回答
如果您从System.currentTimeMillis()获取时间戳，那么您的时间变量应该是长变量。
其他回答
Byte Stream Reader Elapsed Time for 23.7 MB is 96 secs
import java.io.*;
import java.io.IOException;
import java.util.Scanner;
class ElaspedTimetoCopyAFileUsingByteStream
{
private long startTime = 0;
private long stopTime = 0;
private boolean running = false;
public void start()
{
this.startTime = System.currentTimeMillis();
this.running = true;
}
public void stop()
{
this.stopTime = System.currentTimeMillis();
this.running = false;
}
public long getElapsedTime()
{
long elapsed;
if (running) {
elapsed = (System.currentTimeMillis() - startTime);
}
else {
elapsed = (stopTime - startTime);
}
return elapsed;
}
public long getElapsedTimeSecs()
{
long elapsed;
if (running)
{
elapsed = ((System.currentTimeMillis() - startTime) / 1000);
}
else
{
elapsed = ((stopTime - startTime) / 1000);
}
return elapsed;
}
public static void main(String[] args) throws IOException
{
ElaspedTimetoCopyAFileUsingByteStream s = new ElaspedTimetoCopyAFileUsingByteStream();
s.start();
FileInputStream in = null;
FileOutputStream out = null;
try {
in = new FileInputStream("vowels.txt"); // 23.7 MB File
out = new FileOutputStream("output.txt");
int c;
while ((c = in.read()) != -1) {
out.write(c);
}
}finally {
if (in != null) {
in.close();
}
if (out != null) {
out.close();
}
}
s.stop();
System.out.println("elapsed time in seconds: " + s.getElapsedTimeSecs());
}
}
[Elapsed Time for Byte Stream Reader][1]
**Character Stream Reader Elapsed Time for 23.7 MB is 3 secs**
import java.io.*;
import java.io.IOException;
import java.util.Scanner;
class ElaspedTimetoCopyAFileUsingCharacterStream
{
private long startTime = 0;
private long stopTime = 0;
private boolean running = false;
public void start()
{
this.startTime = System.currentTimeMillis();
this.running = true;
}
public void stop()
{
this.stopTime = System.currentTimeMillis();
this.running = false;
}
public long getElapsedTime()
{
long elapsed;
if (running) {
elapsed = (System.currentTimeMillis() - startTime);
}
else {
elapsed = (stopTime - startTime);
}
return elapsed;
}
public long getElapsedTimeSecs()
{
long elapsed;
if (running)
{
elapsed = ((System.currentTimeMillis() - startTime) / 1000);
}
else
{
elapsed = ((stopTime - startTime) / 1000);
}
return elapsed;
}
public static void main(String[] args) throws IOException
{
ElaspedTimetoCopyAFileUsingCharacterStream s = new ElaspedTimetoCopyAFileUsingCharacterStream();
s.start();
FileReader in = null; // CharacterStream Reader
FileWriter out = null;
try {
in = new FileReader("vowels.txt"); // 23.7 MB
out = new FileWriter("output.txt");
int c;
while ((c = in.read()) != -1) {
out.write(c);
}
}finally {
if (in != null) {
in.close();
}
if (out != null) {
out.close();
}
}
s.stop();
System.out.println("elapsed time in seconds: " + s.getElapsedTimeSecs());
}
}
[Elapsed Time for Character Stream Reader][2]
[1]: https://i.stack.imgur.com/hYo8y.png
[2]: https://i.stack.imgur.com/xPjCK.png
用这个:
SimpleDateFormat format = new SimpleDateFormat("HH:mm");
Date d1 = format.parse(strStartTime);
Date d2 = format.parse(strEndTime);
long diff = d2.getTime() - d1.getTime();
long diffSeconds,diffMinutes,diffHours;
if (diff > 0) {
diffSeconds = diff / 1000 % 60;
diffMinutes = diff / (60 * 1000) % 60;
diffHours = diff / (60 * 60 * 1000);
}
else{
long diffpos = (24*((60 * 60 * 1000))) + diff;
diffSeconds = diffpos / 1000 % 60;
diffMinutes = diffpos / (60 * 1000) % 60;
diffHours = (diffpos / (60 * 60 * 1000));
}
(同样重要的是，例如，如果startTime是23:00,endTime是1:00，则持续时间为2:00。)
“else”部分可以得到正确的答案
我建立了一个格式化函数，基于我偷来的东西。我需要一种方法来“分析”日志消息中的内容，所以我需要一个固定长度的持续时间消息。
public static String GetElapsed(long aInitialTime, long aEndTime, boolean aIncludeMillis)
{
StringBuffer elapsed = new StringBuffer();
Map<String, Long> units = new HashMap<String, Long>();
long milliseconds = aEndTime - aInitialTime;
long seconds = milliseconds / 1000;
long minutes = milliseconds / (60 * 1000);
long hours = milliseconds / (60 * 60 * 1000);
long days = milliseconds / (24 * 60 * 60 * 1000);
units.put("milliseconds", milliseconds);
units.put("seconds", seconds);
units.put("minutes", minutes);
units.put("hours", hours);
units.put("days", days);
if (days > 0)
{
long leftoverHours = hours % 24;
units.put("hours", leftoverHours);
}
if (hours > 0)
{
long leftoeverMinutes = minutes % 60;
units.put("minutes", leftoeverMinutes);
}
if (minutes > 0)
{
long leftoverSeconds = seconds % 60;
units.put("seconds", leftoverSeconds);
}
if (seconds > 0)
{
long leftoverMilliseconds = milliseconds % 1000;
units.put("milliseconds", leftoverMilliseconds);
}
elapsed.append(PrependZeroIfNeeded(units.get("days")) + " days ")
.append(PrependZeroIfNeeded(units.get("hours")) + " hours ")
.append(PrependZeroIfNeeded(units.get("minutes")) + " minutes ")
.append(PrependZeroIfNeeded(units.get("seconds")) + " seconds ")
.append(PrependZeroIfNeeded(units.get("milliseconds")) + " ms");
return elapsed.toString();
}
private static String PrependZeroIfNeeded(long aValue)
{
return aValue < 10 ? "0" + aValue : Long.toString(aValue);
}
和一个测试类:
import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;
import junit.framework.TestCase;
public class TimeUtilsTest extends TestCase
{
public void testGetElapsed()
{
long start = System.currentTimeMillis();
GregorianCalendar calendar = (GregorianCalendar) Calendar.getInstance();
calendar.setTime(new Date(start));
calendar.add(Calendar.MILLISECOND, 610);
calendar.add(Calendar.SECOND, 35);
calendar.add(Calendar.MINUTE, 5);
calendar.add(Calendar.DAY_OF_YEAR, 5);
long end = calendar.getTimeInMillis();
assertEquals("05 days 00 hours 05 minutes 35 seconds 610 ms", TimeUtils.GetElapsed(start, end, true));
}
}
如果您从System.currentTimeMillis()获取时间戳，那么您的时间变量应该是长变量。
如果你喜欢使用Java的日历API，你可以试试这个，
Date startingTime = Calendar.getInstance().getTime();
//later on
Date now = Calendar.getInstance().getTime();
long timeElapsed = now.getTime() - startingTime.getTime();
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