在我的模型中我有:

class Alias(MyBaseModel):
remote_image = models.URLField(
    max_length=500, null=True,
    help_text='''
        A URL that is downloaded and cached for the image.
        Only used when the alias is made
    '''
)
    image = models.ImageField(
        upload_to='alias', default='alias-default.png',
        help_text="An image representing the alias"
    )

    
    def save(self, *args, **kw):
        if (not self.image or self.image.name == 'alias-default.png') and self.remote_image :
            try :
                data = utils.fetch(self.remote_image)
                image = StringIO.StringIO(data)
                image = Image.open(image)
                buf = StringIO.StringIO()
                image.save(buf, format='PNG')
                self.image.save(
                    hashlib.md5(self.string_id).hexdigest() + ".png", ContentFile(buf.getvalue())
                )
            except IOError :
                pass

这在remote_image第一次改变的时候工作得很好。

当有人修改了别名上的remote_image时,我如何获取一个新的图像?其次,是否有更好的方法来缓存远程映像?


当前回答

如果你正在使用一个表单,你可以使用表单的changed_data (docs):

class AliasForm(ModelForm):

    def save(self, commit=True):
        if 'remote_image' in self.changed_data:
            # do things
            remote_image = self.cleaned_data['remote_image']
            do_things(remote_image)
        super(AliasForm, self).save(commit)

    class Meta:
        model = Alias

其他回答

本质上,你想要重写模型的__init__方法。模型,以便保留原始值的副本。这使得您不必再执行另一个DB查找(这总是一件好事)。

    class Person(models.Model):
        name = models.CharField()

        __original_name = None

        def __init__(self, *args, **kwargs):
            super().__init__(*args, **kwargs)
            self.__original_name = self.name

        def save(self, force_insert=False, force_update=False, *args, **kwargs):
            if self.name != self.__original_name:
                # name changed - do something here

            super().save(force_insert, force_update, *args, **kwargs)
            self.__original_name = self.name

你可以使用django-model-changes来做到这一点,而不需要额外的数据库查询:

from django.dispatch import receiver
from django_model_changes import ChangesMixin

class Alias(ChangesMixin, MyBaseModel):
   # your model

@receiver(pre_save, sender=Alias)
def do_something_if_changed(sender, instance, **kwargs):
    if 'remote_image' in instance.changes():
        # do something

最佳的解决方案可能是在保存模型实例之前不包括额外的数据库读取操作,也不包括任何进一步的django库。这就是为什么拉弗斯特的解决方案更可取。在管理站点的上下文中,可以简单地覆盖save_model-方法,并调用表单的has_changed方法,就像上面Sion的回答一样。你得到了类似这样的东西,利用Sion的例子设置,但使用changed_data来获得每一个可能的变化:

class ModelAdmin(admin.ModelAdmin):
   fields=['name','mode']
   def save_model(self, request, obj, form, change):
     form.changed_data #output could be ['name']
     #do somethin the changed name value...
     #call the super method
     super(self,ModelAdmin).save_model(request, obj, form, change)

覆盖save_model:

https://docs.djangoproject.com/en/1.10/ref/contrib/admin/#django.contrib.admin.ModelAdmin.save_model

为字段内置changed_data-method:

https://docs.djangoproject.com/en/1.10/ref/forms/api/#django.forms.Form.changed_data

最好的方法是使用pre_save信号。在09年这个问题被提出并回答的时候,可能还没有这个选项,但今天看到这个问题的人应该这样做:

@receiver(pre_save, sender=MyModel)
def do_something_if_changed(sender, instance, **kwargs):
    try:
        obj = sender.objects.get(pk=instance.pk)
    except sender.DoesNotExist:
        pass # Object is new, so field hasn't technically changed, but you may want to do something else here.
    else:
        if not obj.some_field == instance.some_field: # Field has changed
            # do something

注意,字段更改跟踪在django-model-utils中是可用的。

https://django-model-utils.readthedocs.org/en/latest/index.html