对于简单的情况，你可以使用现代字符串格式(简化的Sven的答案): f ' {column1_value: 15} {column2_value}’:

table = {
    'Amplitude': [round(amplitude, 3), 'm³/h'],
    'MAE': [round(mae, 2), 'm³/h'],
    'MAPE': [round(mape, 2), '%'],
}

for metric, value in table.items():
    print(f'{metric:14} : {value[0]:>6.3f} {value[1]}')

输出:

Amplitude      :  1.438 m³/h
MAE            :  0.171 m³/h
MAPE           : 27.740 %

来源:https://docs.python.org/3/tutorial/inputoutput.html formatted-string-literals

当我这样做时，我喜欢对表格的格式细节有一定的控制。特别是，我希望标题单元格与主体单元格具有不同的格式，并且表列的宽度仅为每个列所需的宽度。以下是我的解决方案:

def format_matrix(header, matrix,
                  top_format, left_format, cell_format, row_delim, col_delim):
    table = [[''] + header] + [[name] + row for name, row in zip(header, matrix)]
    table_format = [['{:^{}}'] + len(header) * [top_format]] \
                 + len(matrix) * [[left_format] + len(header) * [cell_format]]
    col_widths = [max(
                      len(format.format(cell, 0))
                      for format, cell in zip(col_format, col))
                  for col_format, col in zip(zip(*table_format), zip(*table))]
    return row_delim.join(
               col_delim.join(
                   format.format(cell, width)
                   for format, cell, width in zip(row_format, row, col_widths))
               for row_format, row in zip(table_format, table))

print format_matrix(['Man Utd', 'Man City', 'T Hotspur', 'Really Long Column'],
                    [[1, 2, 1, -1], [0, 1, 0, 5], [2, 4, 2, 2], [0, 1, 0, 6]],
                    '{:^{}}', '{:<{}}', '{:>{}.3f}', '\n', ' | ')

输出如下:

                   | Man Utd | Man City | T Hotspur | Really Long Column
Man Utd            |   1.000 |    2.000 |     1.000 |             -1.000
Man City           |   0.000 |    1.000 |     0.000 |              5.000
T Hotspur          |   2.000 |    4.000 |     2.000 |              2.000
Really Long Column |   0.000 |    1.000 |     0.000 |              6.000

一些特别的代码:

row_format ="{:>15}" * (len(teams_list) + 1)
print(row_format.format("", *teams_list))
for team, row in zip(teams_list, data):
    print(row_format.format(team, *row))

这依赖于str.format()和格式规范迷你语言。

要使用terminaltables创建一个简单的表，打开终端或命令提示符并运行pip install terminaltables。

你可以像下面这样打印Python列表:

from terminaltables import AsciiTable

l = [
  ['Head', 'Head'],
  ['R1 C1', 'R1 C2'],
  ['R2 C1', 'R2 C2'],
  ['R3 C1', 'R3 C2']
]

table = AsciiTable(l)
print(table.table)

将Sven Marnach的答案更新到Python 3.4中:

row_format ="{:>15}" * (len(teams_list) + 1)
print(row_format.format("", *teams_list))
for team, row in zip(teams_list, data):
    print(row_format.format(team, *row))

list1 = [1, 2, 3]
list2 = [10, 20, 30]

l = []

for i in range(0, len(list1)):
    l.append(list1[i]), l.append(list2[i])

# print(l)

for i in range(0, len(l), 2):
    print(l[i], "", l[i + 1])