你可以使用预定义的实用程序类型Record<Keys, type >:

const obj: Record<string, string> = {
  property: "value",
};

它允许为你的对象文字指定键:

type Keys = "prop1" | "prop2"

const obj: Record<Keys, string> = {
  prop1: "Hello",
  prop2: "Aloha",
  something: "anything" // TS Error: Type '{ prop1: string; prop2: string; something: string; }' is not assignable to type 'Record<Keys, string>'.
                        //   Object literal may only specify known properties, and 'something' does not exist in type 'Record<Keys, string>'.
};

属性值的类型:

type Keys = "prop1" | "prop2"
type Value = "Hello" | "Aloha"

const obj1: Record<Keys, Value> = {
  prop1: "Hello",
  prop2: "Hey", // TS Error: Type '"Hey"' is not assignable to type 'Value'.
};

如果你试图向一个解构对象字面量添加类型，例如在函数的参数中，语法是:

function foo({ bar, baz }: { bar: boolean, baz: string }) {
  // ...
}

foo({ bar: true, baz: 'lorem ipsum' });

只是扩展@RickLove的回复…

这很好，因为你只需要定义不能推断的类型:

const initialState = { 
   user: undefined as User | undefined, 
   userLoading: false
}; 

它被编译成下面的js代码:

const initialState = { 
   user: undefined, 
   userLoading: false
};  

如果你需要把它提取成一个类型，你可以这样做:

export type InitState = typeof initialState;

你已经很接近了，你只需要用a:替换=。您可以使用对象类型文字(参见规范第3.5.3节)或接口。使用对象类型文字接近于你所拥有的:

var obj: { property: string; } = { property: "foo" };

但是你也可以使用接口

interface MyObjLayout {
    property: string;
}

var obj: MyObjLayout = { property: "foo" };

如果你试图写一个类型注释，语法是:

var x: { property: string; } = { property: 'hello' };

如果你试图写一个对象文字，语法是:

var x = { property: 'hello' };

您的代码试图在值位置使用类型名称。

// Use ..

const Per = {
  name: 'HAMZA',
  age: 20,
  coords: {
    tele: '09',
    lan: '190'
  },
  setAge(age: Number): void {
    this.age = age;
  },
  getAge(): Number {
    return age;
  }
};
const { age, name }: { age: Number; name: String } = Per;
const {
  coords: { tele, lan }
}: { coords: { tele: String; lan: String } } = Per;

console.log(Per.getAge());