在有年、月、日、时、分的情况下,如何根据设备配置的日期和时间正确格式化?


当前回答

下面是:http://developer.android.com/reference/android/text/format/Time.html

最好使用Android原生的Time类:

Time now = new Time();
now.setToNow();

然后格式:

Log.d("DEBUG", "Time "+now.format("%d.%m.%Y %H.%M.%S"));

其他回答

我是这样使用的:

public class DateUtils {
    static DateUtils instance;
    private final DateFormat dateFormat;
    private final DateFormat timeFormat;

    private DateUtils() {
        dateFormat = android.text.format.DateFormat.getDateFormat(MainApplication.context);
        timeFormat = android.text.format.DateFormat.getTimeFormat(MainApplication.context);
    }

    public static DateUtils getInstance() {
        if (instance == null) {
            instance = new DateUtils();
        }
        return instance;
    }

    public synchronized static String formatDateTime(long timestamp) {
        long milliseconds = timestamp * 1000;
        Date dateTime = new Date(milliseconds);
        String date = getInstance().dateFormat.format(dateTime);
        String time = getInstance().timeFormat.format(dateTime);
        return date + " " + time;
    }
}

这是我的方法,可以定义和输入输出格式。

public static String formattedDateFromString(String inputFormat, String outputFormat, String inputDate){
    if(inputFormat.equals("")){ // if inputFormat = "", set a default input format.
        inputFormat = "yyyy-MM-dd hh:mm:ss";
    }
    if(outputFormat.equals("")){
        outputFormat = "EEEE d 'de' MMMM 'del' yyyy"; // if inputFormat = "", set a default output format.
    }
    Date parsed = null;
    String outputDate = "";

    SimpleDateFormat df_input = new SimpleDateFormat(inputFormat, java.util.Locale.getDefault());
    SimpleDateFormat df_output = new SimpleDateFormat(outputFormat, java.util.Locale.getDefault());

    // You can set a different Locale, This example set a locale of Country Mexico.
    //SimpleDateFormat df_input = new SimpleDateFormat(inputFormat, new Locale("es", "MX"));
    //SimpleDateFormat df_output = new SimpleDateFormat(outputFormat, new Locale("es", "MX"));

    try {
        parsed = df_input.parse(inputDate);
        outputDate = df_output.format(parsed);
    } catch (Exception e) { 
        Log.e("formattedDateFromString", "Exception in formateDateFromstring(): " + e.getMessage());
    }
    return outputDate;

}

最短的方法:

// 2019-03-29 16:11
String.format("%1$tY-%<tm-%<td %<tR", Calendar.getInstance())

%tR是%tH:%tM的缩写,<表示重用最后一个参数(1$)。

它等价于String。格式(“% 1 $ tY - % 1 $ tm - td % 1 $ % 1 $ tH: % 1 $ tm”,Calendar.getInstance ())

https://developer.android.com/reference/java/util/Formatter.html

使用Time类中的构建!

Time time = new Time();
time.set(0, 0, 17, 4, 5, 1999);
Log.i("DateTime", time.format("%d.%m.%Y %H:%M:%S"));

这个代码为我工作!

Date d = new Date();
    CharSequence s = android.text.format.DateFormat.format("MM-dd-yy hh-mm-ss",d.getTime());
    Toast.makeText(this,s.toString(),Toast.LENGTH_SHORT).show();