如果你想从左边和右边修剪指定数量的空格，你可以这样做:

def remove_outer_spaces(text, num_of_leading, num_of_trailing):
    text = list(text)
    for i in range(num_of_leading):
        if text[i] == " ":
            text[i] = ""
        else:
            break

    for i in range(1, num_of_trailing+1):
        if text[-i] == " ":
            text[-i] = ""
        else:
            break
    return ''.join(text)

txt1 = "   MY name is     "
print(remove_outer_spaces(txt1, 1, 1))  # result is: "  MY name is    "
print(remove_outer_spaces(txt1, 2, 3))  # result is: " MY name is  "
print(remove_outer_spaces(txt1, 6, 8))  # result is: "MY name is"

一种方法是使用.strip()方法(删除所有周围的空白)

str = "  Hello World  "
str = str.strip()
**result: str = "Hello World"**

请注意，.strip()返回字符串的副本，并且不会更改下划线对象(因为字符串是不可变的)。

如果您希望删除所有空白(不仅仅是修剪边缘):

str = ' abcd efgh ijk  '
str = str.replace(' ', '')
**result: str = 'abcdefghijk'

这也可以用正则表达式来实现

import re

input  = " Hello "
output = re.sub(r'^\s+|\s+$', '', input)
# output = 'Hello'

Strip也不局限于空白字符:

# remove all leading/trailing commas, periods and hyphens
title = title.strip(',.-')

这将删除myString中所有前导和尾部的空格:

myString.strip()

你需要strip():

myphrases = [" Hello ", " Hello", "Hello ", "Bob has a cat"]

for phrase in myphrases:
    print(phrase.strip())