你可以使用DateTime::createFromFormat()来实现这个目的:

function validateDate($date, $format = 'Y-m-d')
{
    $d = DateTime::createFromFormat($format, $date);
    // The Y ( 4 digits year ) returns TRUE for any integer with any number of digits so changing the comparison from == to === fixes the issue.
    return $d && $d->format($format) === $date;
}

[从这个答案中得到的函数。在php.net上也有。原作者:格拉维克。

测试用例:

var_dump(validateDate('2013-13-01'));  // false
var_dump(validateDate('20132-13-01')); // false
var_dump(validateDate('2013-11-32'));  // false
var_dump(validateDate('2012-2-25'));   // false
var_dump(validateDate('2013-12-01'));  // true
var_dump(validateDate('1970-12-01'));  // true
var_dump(validateDate('2012-02-29'));  // true
var_dump(validateDate('2012', 'Y'));   // true
var_dump(validateDate('12012', 'Y'));  // false

演示!

试试这个:

$myday = '2022-1-30'; 
if (($timestamp = strtotime($myday)) === false) {
    echo 'The string ('.$myday.') is not date';
} else {
    echo 'The string ('.$myday.') is date = ' . date('l dS \o\f F Y h:i:s A', $timestamp);
}

使用php预构建函数的简单方式:

function checkmydate($date) {
  $tempDate = explode('-', $date);
  // checkdate(month, day, year)
  return checkdate($tempDate[1], $tempDate[2], $tempDate[0]);
}

Test

   checkmydate('2015-12-01'); //true
   checkmydate('2015-14-04'); //false

    /**** date check is a recursive function. it's need 3 argument 
    MONTH,DAY,YEAR. ******/

    $always_valid_date = $this->date_check($month,$day,$year);

    private function date_check($month,$day,$year){

        /** checkdate() is a php function that check a date is valid 
        or not. if valid date it's return true else false.   **/

        $status = checkdate($month,$day,$year);

        if($status == true){

            $always_valid_date = $year . '-' . $month . '-' . $day;

            return $always_valid_date;

        }else{
            $day = ($day - 1);

            /**recursive call**/

            return $this->date_check($month,$day,$year);
        }

    }

使用checkdate函数验证:

$date = '2019-02-30';

$date_parts = explode( '-', $date );

if(checkdate( $date_parts[1], $date_parts[2], $date_parts[0] )){
    //date is valid
}else{
    //date is invalid
}

你也可以解析月份日期和年份的日期，然后你可以使用PHP函数checkdate()，你可以在这里读到:http://php.net/manual/en/function.checkdate.php

你也可以试试这个:

$date="2013-13-01";

if (preg_match("/^[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])$/",$date))
    {
        echo 'Date is valid';
    }else{
        echo 'Date is invalid';
    }