另一种以分钟为单位计算差异的简单方法。请注意，这是一个在1年范围内计算的样本。详情请点击这里

$origin = new DateTime('2021-02-10 09:46:32');
$target = new DateTime('2021-02-11 09:46:32');
$interval = $origin->diff($target);
echo (($interval->format('%d')*24) + $interval->format('%h'))*60; //1440 (difference in minutes)

这将有助于....

function get_time($date,$nosuffix=''){
    $datetime = new DateTime($date);
    $interval = date_create('now')->diff( $datetime );
    if(empty($nosuffix))$suffix = ( $interval->invert ? ' ago' : '' );
    else $suffix='';
    //return $interval->y;
    if($interval->y >=1)        {$count = date(VDATE, strtotime($date)); $text = '';}
    elseif($interval->m >=1)    {$count = date('M d', strtotime($date)); $text = '';}
    elseif($interval->d >=1)    {$count = $interval->d; $text = 'day';} 
    elseif($interval->h >=1)    {$count = $interval->h; $text = 'hour';}
    elseif($interval->i >=1)    {$count = $interval->i; $text = 'minute';}
    elseif($interval->s ==0)    {$count = 'Just Now'; $text = '';}
    else                        {$count = $interval->s; $text = 'second';}
    if(empty($text)) return '<i class="fa fa-clock-o"></i> '.$count;
    return '<i class="fa fa-clock-o"></i> '.$count.(($count ==1)?(" $text"):(" ${text}s")).' '.$suffix;     
}

我找到了很多解，但我从来没有得到正确的解。但是我已经创建了一些代码来查找分钟，请检查它。

<?php

  $time1 = "23:58";
  $time2 = "01:00";
  $time1 = explode(':',$time1);
  $time2 = explode(':',$time2);
  $hours1 = $time1[0];
  $hours2 = $time2[0];
  $mins1 = $time1[1];
  $mins2 = $time2[1];
  $hours = $hours2 - $hours1;
  $mins = 0;
  if($hours < 0)
  {
    $hours = 24 + $hours;
  }
  if($mins2 >= $mins1) {
        $mins = $mins2 - $mins1;
    }
    else {
      $mins = ($mins2 + 60) - $mins1;
      $hours--;
    }
    if($mins < 9)
    {
      $mins = str_pad($mins, 2, '0', STR_PAD_LEFT);
    }
    if($hours < 9)
    {
      $hours =str_pad($hours, 2, '0', STR_PAD_LEFT);
    }
echo $hours.':'.$mins;
?>

它以小时和分钟为单位输出，例如01小时02分钟，如01:02

这就是我如何显示“xx次前”在php > 5.2 ..这里是DateTime对象的更多信息

//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate);    // output: 23 hrs ago

// Return the value of time different in "xx times ago" format
function ago($timestamp)
{

    $today = new DateTime(date('y-m-d h:i:s')); // [2]
    //$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
    $thatDay = new DateTime($timestamp);
    $dt = $today->diff($thatDay);

    if ($dt->y > 0){
        $number = $dt->y;
        $unit = "year";
    } else if ($dt->m > 0) {
        $number = $dt->m;
        $unit = "month";
    } else if ($dt->d > 0) {
        $number = $dt->d;
        $unit = "day";
    } else if ($dt->h > 0) {
        $number = $dt->h;
        $unit = "hour";
    } else if ($dt->i > 0) {
        $number = $dt->i;
        $unit = "minute";
    } else if ($dt->s > 0) {
        $number = $dt->s;
        $unit = "second";
    }
    
    $unit .= $number  > 1 ? "s" : "";
 
    $ret = $number." ".$unit." "."ago";
    return $ret;
}

另一种以分钟为单位计算差异的简单方法。请注意，这是一个在1年范围内计算的样本。详情请点击这里

$origin = new DateTime('2021-02-10 09:46:32');
$target = new DateTime('2021-02-11 09:46:32');
$interval = $origin->diff($target);
echo (($interval->format('%d')*24) + $interval->format('%h'))*60; //1440 (difference in minutes)

function date_getFullTimeDifference( $start, $end )
{
$uts['start']      =    strtotime( $start );
        $uts['end']        =    strtotime( $end );
        if( $uts['start']!==-1 && $uts['end']!==-1 )
        {
            if( $uts['end'] >= $uts['start'] )
            {
                $diff    =    $uts['end'] - $uts['start'];
                if( $years=intval((floor($diff/31104000))) )
                    $diff = $diff % 31104000;
                if( $months=intval((floor($diff/2592000))) )
                    $diff = $diff % 2592000;
                if( $days=intval((floor($diff/86400))) )
                    $diff = $diff % 86400;
                if( $hours=intval((floor($diff/3600))) )
                    $diff = $diff % 3600;
                if( $minutes=intval((floor($diff/60))) )
                    $diff = $diff % 60;
                $diff    =    intval( $diff );
                return( array('years'=>$years,'months'=>$months,'days'=>$days, 'hours'=>$hours, 'minutes'=>$minutes, 'seconds'=>$diff) );
            }
            else
            {
                echo "Ending date/time is earlier than the start date/time";
            }
        }
        else
        {
            echo "Invalid date/time data detected";
        }
}