使用(正)前向，这样正则表达式就断言特殊字符存在，但实际上并不匹配它:

string.split(/<br \/>(?=&#?[a-zA-Z0-9]+;)/g);

看看它的实际应用:

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _bbbb < br / > &Dagger;亿”; 游戏机log(管柱。斯普利特(/ < br \/>(?=&#?[ a-zA-Z0-9] +) / (g));

Most of the existing answers predate the introduction of lookbehind assertions in JavaScript in 2018. You didn't specify how you wanted the delimiters to be included in the result. One typical use case would be sentences delimited by punctuation ([.?!]), where one would want the delimiters to be included at the ends of the resulting strings. This corresponds to the fourth case in the accepted answer, but as noted there, that solution only works for single characters. Arbitrary strings with the delimiters appended at the end can be formed with a lookbehind assertion:

'It is. Is it? It is!'.split(/(?<=[.?!])/)
/* [ 'It is.', ' Is it?', ' It is!' ] */

回答它这里也JavaScript分割正则表达式保持分隔符

在正则表达式中使用(?=pattern)前向模式 例子

var string = '500x500-11*90~1+1';
string = string.replace(/(?=[$-/:-?{-~!"^_`\[\]])/gi, ",");
string = string.split(",");

这将得到以下结果。

[ '500x500', '-11', '*90', '~1', '+1' ]

还可以直接拆分吗

string = string.split(/(?=[$-/:-?{-~!"^_`\[\]])/gi);

给出相同的结果

[ '500x500', '-11', '*90', '~1', '+1' ]

我知道这有点晚了，但你也可以使用搜索

Var string = "aaaaaa<br />&dagger;bbbb < br / >匕首;预备”; Var数组= string.split(/(?< = < br \ / >) /); console.log(数组);

使用(正)前向，这样正则表达式就断言特殊字符存在，但实际上并不匹配它:

string.split(/<br \/>(?=&#?[a-zA-Z0-9]+;)/g);

看看它的实际应用:

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _bbbb < br / > &Dagger;亿”; 游戏机log(管柱。斯普利特(/ < br \/>(?=&#?[ a-zA-Z0-9] +) / (g));

扩展函数将字符串与子字符串或RegEx分开，分隔符根据第二个参数放在前面或后面。

    String.prototype.splitKeep = function (splitter, ahead) {
        var self = this;
        var result = [];
        if (splitter != '') {
            var matches = [];
            // Getting mached value and its index
            var replaceName = splitter instanceof RegExp ? "replace" : "replaceAll";
            var r = self[replaceName](splitter, function (m, i, e) {
                matches.push({ value: m, index: i });
                return getSubst(m);
            });
            // Finds split substrings
            var lastIndex = 0;
            for (var i = 0; i < matches.length; i++) {
                var m = matches[i];
                var nextIndex = ahead == true ? m.index : m.index + m.value.length;
                if (nextIndex != lastIndex) {
                    var part = self.substring(lastIndex, nextIndex);
                    result.push(part);
                    lastIndex = nextIndex;
                }
            };
            if (lastIndex < self.length) {
                var part = self.substring(lastIndex, self.length);
                result.push(part);
            };
            // Substitution of matched string
            function getSubst(value) {
                var substChar = value[0] == '0' ? '1' : '0';
                var subst = '';
                for (var i = 0; i < value.length; i++) {
                    subst += substChar;
                }
                return subst;
            };
        }
        else {
            result.add(self);
        };
        return result;
    };

测试:

    test('splitKeep', function () {
        // String
        deepEqual("1231451".splitKeep('1'), ["1", "231", "451"]);
        deepEqual("123145".splitKeep('1', true), ["123", "145"]);
        deepEqual("1231451".splitKeep('1', true), ["123", "145", "1"]);
        deepEqual("hello man how are you!".splitKeep(' '), ["hello ", "man ", "how ", "are ", "you!"]);
        deepEqual("hello man how are you!".splitKeep(' ', true), ["hello", " man", " how", " are", " you!"]);
        // Regex
        deepEqual("mhellommhellommmhello".splitKeep(/m+/g), ["m", "hellomm", "hellommm", "hello"]);
        deepEqual("mhellommhellommmhello".splitKeep(/m+/g, true), ["mhello", "mmhello", "mmmhello"]);
    });