等待ExecutorService所有任务完成的最简单方法是什么?我的任务主要是计算性的，所以我只想运行大量的作业——每个核心上都有一个。现在我的设置是这样的:
ExecutorService es = Executors.newFixedThreadPool(2);
for (DataTable singleTable : uniquePhrases) {
es.execute(new ComputeDTask(singleTable));
}
try{
es.wait();
}
catch (InterruptedException e){
e.printStackTrace();
}
ComputeDTask实现了runnable。这似乎正确地执行了任务，但代码在wait()时崩溃，并出现IllegalMonitorStateException。这是奇怪的，因为我玩了一些玩具的例子，它似乎工作。
uniquePhrases包含数万个元素。我应该用另一种方法吗?我在寻找一些尽可能简单的东西
当前回答
一个简单的替代方法是使用线程和join。 参考:连接线程
其他回答
听起来好像你需要ForkJoinPool并使用全局池来执行任务。
public static void main(String[] args) {
// the default `commonPool` should be sufficient for many cases.
ForkJoinPool pool = ForkJoinPool.commonPool();
// The root of your task that may spawn other tasks.
// Make sure it submits the additional tasks to the same executor that it is in.
Runnable rootTask = new YourTask(pool);
pool.execute(rootTask);
pool.awaitQuiescence(...);
// that's it.
}
美在泳池里。awaitQuiescence方法将阻塞利用调用者的线程来执行它的任务，然后当它真的为空时返回。
有几种方法。
您可以调用第一个ExecutorService。shutdown，然后ExecutorService。返回:
如果该执行程序终止，则为True;如果超时，则为false 在终止之前
So:
有一个叫awaitterminate的函数，但是必须有一个超时 它提供了。这并不能保证当它返回全部时 任务早就完成了。有办法实现这个目标吗?
你只需要在循环中调用awaitterminate。
使用awaitTermination:
这个实现的完整示例:
public class WaitForAllToEnd {
public static void main(String[] args) throws InterruptedException {
final int total_threads = 4;
ExecutorService executor = Executors.newFixedThreadPool(total_threads);
for(int i = 0; i < total_threads; i++){
executor.execute(parallelWork(100 + i * 100));
}
int count = 0;
// This is the relevant part
// Chose the delay most appropriate for your use case
executor.shutdown();
while (!executor.awaitTermination(100, TimeUnit.MILLISECONDS)) {
System.out.println("Waiting "+ count);
count++;
}
}
private static Runnable parallelWork(long sleepMillis) {
return () -> {
try {
Thread.sleep(sleepMillis);
} catch (InterruptedException e) {
// Do Something
}
System.out.println("I am Thread : " + Thread.currentThread().getId());
};
}
}
使用CountDownLatch:
另一种选择是创建CountDownLatch，其计数等于并行任务的数量。每个线程调用countDownLatch.countDown();，而主线程调用countDownLatch.await();。
这个实现的完整示例:
public class WaitForAllToEnd {
public static void main(String[] args) throws InterruptedException {
final int total_threads = 4;
CountDownLatch countDownLatch = new CountDownLatch(total_threads);
ExecutorService executor = Executors.newFixedThreadPool(total_threads);
for(int i = 0; i < total_threads; i++){
executor.execute(parallelWork(100 + i * 100, countDownLatch));
}
countDownLatch.await();
System.out.println("Exit");
executor.shutdown();
}
private static Runnable parallelWork(long sleepMillis, CountDownLatch countDownLatch) {
return () -> {
try {
Thread.sleep(sleepMillis);
} catch (InterruptedException e) {
// Do Something
}
System.out.println("I am Thread : " + Thread.currentThread().getId());
countDownLatch.countDown();
};
}
}
使用CyclicBarrier:
另一种方法是使用循环屏障
public class WaitForAllToEnd {
public static void main(String[] args) throws InterruptedException, BrokenBarrierException {
final int total_threads = 4;
CyclicBarrier barrier = new CyclicBarrier(total_threads+ 1);
ExecutorService executor = Executors.newFixedThreadPool(total_threads);
for(int i = 0; i < total_threads; i++){
executor.execute(parallelWork(100 + i * 100, barrier));
}
barrier.await();
System.out.println("Exit");
executor.shutdown();
}
private static Runnable parallelWork(long sleepMillis, CyclicBarrier barrier) {
return () -> {
try {
Thread.sleep(sleepMillis);
} catch (InterruptedException e) {
// Do Something
}
System.out.println("I am Thread : " + Thread.currentThread().getId());
try {
barrier.await();
} catch (InterruptedException | BrokenBarrierException e) {
// Do something
}
};
}
}
还有其他方法，但这些方法需要对您的初始需求进行更改，即:
当任务提交时，如何等待所有任务完成 使用ExecutorService.execute()。
您可以使用ExecutorService。它将执行所有任务并等待所有线程完成它们的任务。
这是完整的javadoc
您还可以使用此方法的重载版本来指定超时时间。
下面是ExecutorService.invokeAll的示例代码
public class Test {
public static void main(String[] args) throws InterruptedException, ExecutionException {
ExecutorService service = Executors.newFixedThreadPool(3);
List<Callable<String>> taskList = new ArrayList<>();
taskList.add(new Task1());
taskList.add(new Task2());
List<Future<String>> results = service.invokeAll(taskList);
for (Future<String> f : results) {
System.out.println(f.get());
}
}
}
class Task1 implements Callable<String> {
@Override
public String call() throws Exception {
try {
Thread.sleep(2000);
return "Task 1 done";
} catch (Exception e) {
e.printStackTrace();
return " error in task1";
}
}
}
class Task2 implements Callable<String> {
@Override
public String call() throws Exception {
try {
Thread.sleep(3000);
return "Task 2 done";
} catch (Exception e) {
e.printStackTrace();
return " error in task2";
}
}
}
只使用
latch = new CountDownLatch(noThreads)
在每个线程中
latch.countDown();
作为屏障
latch.await();
这个怎么样?
Object lock = new Object();
CountDownLatch cdl = new CountDownLatch(threadNum);
for (int i = 0; i < threadNum; i++) {
executorService.execute(() -> {
synchronized (lock) {
cdl.countDown();
try {
lock.wait();
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
}
}
});
}
cdl.await();
synchronized (lock) {
lock.notifyAll();
}
如果您没有向ExecutorService添加新任务，这可能会等待所有当前任务完成
