来自:http://jquery-howto.blogspot.com/2009/09/get-url-parameters-values-with-jquery.html

这是你需要的:)

下面的代码将返回一个包含URL参数的JavaScript对象:

// Read a page's GET URL variables and return them as an associative array.
function getUrlVars()
{
    var vars = [], hash;
    var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&');
    for(var i = 0; i < hashes.length; i++)
    {
        hash = hashes[i].split('=');
        vars.push(hash[0]);
        vars[hash[0]] = hash[1];
    }
    return vars;
}

例如，如果你有URL:

http://www.example.com/?me=myValue&name2=SomeOtherValue

这段代码将返回:

{
    "me"    : "myValue",
    "name2" : "SomeOtherValue"
}

你可以这样做:

var me = getUrlVars()["me"];
var name2 = getUrlVars()["name2"];

看看Stack Overflow给出的答案。

 function getParameterByName(name, url) {
     if (!url) url = window.location.href;
     name = name.replace(/[\[\]]/g, "\\$&");
     var regex = new RegExp("[?&]" + name + "(=([^&#]*)|&|#|$)"),
         results = regex.exec(url);
     if (!results) return null;
     if (!results[2]) return '';
     return decodeURIComponent(results[2].replace(/\+/g, " "));
 }

你可以使用这个方法来动画:

例如:

var thequerystring = getParameterByName("location");
$('html,body').animate({scrollTop: $("div#" + thequerystring).offset().top}, 500);

一个简单的方法来做到这一点与一些jQuery和直接JavaScript，只是查看您的控制台在Chrome或Firefox看到输出…

  var queries = {};
  $.each(document.location.search.substr(1).split('&'),function(c,q){
    var i = q.split('=');
    queries[i[0].toString()] = i[1].toString();
  });
  console.log(queries);

我们是这样做的……

String.prototype.getValueByKey = function (k) {
    var p = new RegExp('\\b' + k + '\\b', 'gi');
    return this.search(p) != -1 ? decodeURIComponent(this.substr(this.search(p) + k.length + 1).substr(0, this.substr(this.search(p) + k.length + 1).search(/(&|;|$)/))) : "";
};

要从当前URL检索整个查询字符串，从?性格，你可以用

location.search

https://developer.mozilla.org/en-US/docs/DOM/window.location

例子:

// URL = https://example.com?a=a%20a&b=b123
console.log(location.search); // Prints "?a=a%20a&b=b123" 

关于检索特定的查询字符串参数，尽管存在URLSearchParams和URL这样的类，但Internet Explorer目前不支持它们，因此应该避免使用。相反，你可以尝试这样做:

/**
 * Accepts either a URL or querystring and returns an object associating 
 * each querystring parameter to its value. 
 *
 * Returns an empty object if no querystring parameters found.
 */
function getUrlParams(urlOrQueryString) {
  if ((i = urlOrQueryString.indexOf('?')) >= 0) {
    const queryString = urlOrQueryString.substring(i+1);
    if (queryString) {
      return _mapUrlParams(queryString);
    } 
  }
  
  return {};
}

/**
 * Helper function for `getUrlParams()`
 * Builds the querystring parameter to value object map.
 *
 * @param queryString {string} - The full querystring, without the leading '?'.
 */
function _mapUrlParams(queryString) {
  return queryString    
    .split('&') 
    .map(function(keyValueString) { return keyValueString.split('=') })
    .reduce(function(urlParams, [key, value]) {
      if (Number.isInteger(parseInt(value)) && parseInt(value) == value) {
        urlParams[key] = parseInt(value);
      } else {
        urlParams[key] = decodeURI(value);
      }
      return urlParams;
    }, {});
}

你可以这样使用上面的语句:

// Using location.search
let urlParams = getUrlParams(location.search); // Assume location.search = "?a=1&b=2b2"
console.log(urlParams); // Prints { "a": 1, "b": "2b2" }

// Using a URL string
const url = 'https://example.com?a=A%20A&b=1';
urlParams = getUrlParams(url);
console.log(urlParams); // Prints { "a": "A A", "b": 1 }

// To check if a parameter exists, simply do:
if (urlParams.hasOwnProperty('parameterName')) { 
  console.log(urlParams.parameterName);
}