typescript用户的另一个解决方案:

import Vue from "vue";
import Component from "vue-class-component";

@Component({
  beforeRouteLeave(to, from, next) {
    // incase if you want to access `this`
    // const self = this as any;
    next();
  }
})

export default class ComponentName extends Vue {}

typescript用户的另一个解决方案:

import Vue from "vue";
import Component from "vue-class-component";

@Component({
  beforeRouteLeave(to, from, next) {
    // incase if you want to access `this`
    // const self = this as any;
    next();
  }
})

export default class ComponentName extends Vue {}

你可以使用beforeEach事件，它允许任何函数在路由改变时发生，只是不要忘记调用next()函数来进行下一个操作，基本上它与后端expressJS中间件具有相同的工作。

router.beforeEach((to, from, next) => {
  store.commit('setError', null); //in this example on each route I'm removing the error noted from the old route
  document.title = `${to.meta.title} | HartWork`; //on each route I'm adding a prefix to document title.
  next(); //calling next to proceed next functions and operations
})

有深度选项的观察者对我没用。

相反，我使用updated()生命周期钩子，每当组件的数据发生变化时执行该钩子。 就像使用mounted()一样使用它。

mounted() {
   /* to be executed when mounted */
},
updated() {
   console.log(this.$route)
}

请参阅文档以供参考。

使用Vue3和合成API你可以做到

<script setup lang="ts">
import { watch } from "vue";
import { useRoute } from "vue-router";

const route = useRoute();

// do a `console.log(route)` to see route attributes (fullPath, hash, params, path...)
watch(
  () => route.fullPath,
  async () => {
    console.log("route fullPath updated", route.fullPath);
  }
);
</script>

参考资料和示例:https://router.vuejs.org/guide/advanced/composition-api.html#vue-router-and-the-composition-api

如果有人正在寻找如何在Typescript中做到这一点，这里是解决方案:

@Watch('$route', { immediate: true, deep: true })
onUrlChange(newVal: Route) {
    // Some action
}

是的，正如下面@Coops提到的，请不要忘记包括:

import { Watch } from 'vue-property-decorator';

编辑: Alcalyn提出了一个很好的观点，使用Route type而不是any:

import { Watch } from 'vue-property-decorator';    
import { Route } from 'vue-router';