试试这个:

var today = new Date();
var date = today.getFullYear()+'-'+(today.getMonth()+1)+'-'+today.getDate();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date+' '+time;

输出:

2022-3-3 15:52:45

这应该可以达到目的:

function dateToString(date) {
    var month = date.getMonth() + 1;
    var day = date.getDate();
    var dateOfString = (("" + day).length < 2 ? "0" : "") + day + "/";
    dateOfString += (("" + month).length < 2 ? "0" : "") + month + "/";
    dateOfString += date.getFullYear();
    return dateOfString;
}

var currentdate = new Date();
var datetime = "Last Sync: ";
datetime += dateToString(currentdate );
datetime += + currentdate.getHours() + ":"
            + currentdate.getMinutes() + ":"
            + currentdate.getSeconds();

. getmonth()返回一个从零开始的数字，所以为了得到正确的月份，你需要加1，所以在五月调用. getmonth()将返回4而不是5。

因此，在代码中，我们可以使用currentdate.getMonth()+1来输出正确的值。此外:

.getDate()返回月份的日期<-这是你想要的 .getDay()是Date对象的一个单独方法，它将返回一个整数，表示一周中的当前日期(0-6)0 ==星期日等

所以你的代码应该是这样的:

var currentdate = new Date(); 
var datetime = "Last Sync: " + currentdate.getDate() + "/"
                + (currentdate.getMonth()+1)  + "/" 
                + currentdate.getFullYear() + " @ "  
                + currentdate.getHours() + ":"  
                + currentdate.getMinutes() + ":" 
                + currentdate.getSeconds();

JavaScript Date实例继承自Date.prototype。您可以修改构造函数的原型对象，以影响JavaScript Date实例继承的属性和方法

您可以使用Date原型对象创建一个新方法，该方法将返回今天的日期和时间。这些新方法或属性将由Date对象的所有实例继承，因此在需要重用此功能时特别有用。

// For todays date;
Date.prototype.today = function () { 
    return ((this.getDate() < 10)?"0":"") + this.getDate() +"/"+(((this.getMonth()+1) < 10)?"0":"") + (this.getMonth()+1) +"/"+ this.getFullYear();
}

// For the time now
Date.prototype.timeNow = function () {
     return ((this.getHours() < 10)?"0":"") + this.getHours() +":"+ ((this.getMinutes() < 10)?"0":"") + this.getMinutes() +":"+ ((this.getSeconds() < 10)?"0":"") + this.getSeconds();
}

然后，您可以通过执行以下操作简单地检索日期和时间:

var newDate = new Date();
var datetime = "LastSync: " + newDate.today() + " @ " + newDate.timeNow();

或者将该方法调用为内联，这样它就是-

var datetime = "LastSync: " + new Date().today() + " @ " + new Date().timeNow();

function UniqueDateTime(format='',language='en-US'){
    //returns a meaningful unique number based on current time, and milliseconds, making it virtually unique
    //e.g : 20170428-115833-547
    //allows personal formatting like more usual :YYYYMMDDHHmmSS, or YYYYMMDD_HH:mm:SS
    var dt = new Date();
    var modele="YYYYMMDD-HHmmSS-mss";
    if (format!==''){
      modele=format;
    }
    modele=modele.replace("YYYY",dt.getFullYear());
    modele=modele.replace("MM",(dt.getMonth()+1).toLocaleString(language, {minimumIntegerDigits: 2, useGrouping:false}));
    modele=modele.replace("DD",dt.getDate().toLocaleString(language, {minimumIntegerDigits: 2, useGrouping:false}));
    modele=modele.replace("HH",dt.getHours().toLocaleString(language, {minimumIntegerDigits: 2, useGrouping:false}));
    modele=modele.replace("mm",dt.getMinutes().toLocaleString(language, {minimumIntegerDigits: 2, useGrouping:false}));
    modele=modele.replace("SS",dt.getSeconds().toLocaleString(language, {minimumIntegerDigits: 2, useGrouping:false}));
    modele=modele.replace("mss",dt.getMilliseconds().toLocaleString(language, {minimumIntegerDigits: 3, useGrouping:false}));
    return modele;
}

<p id="DateTimeBox">点击按钮显示日期和时间 <按钮onclick = " ShowDate ();">显示日期</button> . < >脚本 函数ShowDate() { . getelementbyid(“DateTimeBox”)。innerHTML = Date(); ｝ > < /脚本

我需要在后期特效里弄清楚这一点。以下是我从几个不同的来源获取元素后得出的结论——格式是MM/DD/YYYY HH:MM AM/PM

D = new Date(Date(00));
M = D.getMonth()+1;
H = D.getHours();
Mi = D.getMinutes();

N = "AM"
if (H >= 12)
N = "PM"
if (H > 12)
{
H = H-12
}

amtOfZeroes = 2;
isNeg = false;

if (M < 0)
{
M = Math.abs(M);
isNeg = true;
}
Mo = Math.round(M) + "";
while(Mo.length < amtOfZeroes)
{

Mo = "0" + Mo; 
}
if (isNeg)
Mo = "-" + Mo;

if (H < 0)
{
H = Math.abs(H);
isNeg = true;
}
Ho = Math.round(H) + "";
while(Ho.length < amtOfZeroes)
{
Ho = "0" + Ho; 
}
if (isNeg)
Ho = "-" + Ho;

if (Mi < 0)
{
Mi = Math.abs(Mi);
isNeg = true;
}
Min = Math.round(Mi) + "";
while(Min.length < amtOfZeroes)
{
Min = "0" + Min; 
}
if (isNeg)
Min = "-" + Min;

T = Ho + ":" + (Min)

Mo + "/" + D.getDate() + "/" + D.getFullYear() + "  " + T + " " + N