我有一个脚本，打印当前的日期和时间在JavaScript，但日期总是错误的。代码如下:
var currentdate = new Date();
var datetime = "Last Sync: " + currentdate.getDay() + "/" + currentdate.getMonth()
+ "/" + currentdate.getFullYear() + " @ "
+ currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":" + currentdate.getSeconds();
它应该打印18/04/2012 15:07:33和打印3/3/2012 15:07:33
当前回答
这个问题很古老，答案也很古老。现在我们可以使用moment.js来获取当前日期，而不是那些怪异的函数，这实际上非常简单。所有要做的就是在我们的项目中包括moment.js，并获得一个格式良好的日期，例如，通过:
moment().format("dddd, MMMM Do YYYY, h:mm:ss a");
我认为这使得在javascript中处理日期更容易。
其他回答
我需要在后期特效里弄清楚这一点。以下是我从几个不同的来源获取元素后得出的结论——格式是MM/DD/YYYY HH:MM AM/PM
D = new Date(Date(00));
M = D.getMonth()+1;
H = D.getHours();
Mi = D.getMinutes();
N = "AM"
if (H >= 12)
N = "PM"
if (H > 12)
{
H = H-12
}
amtOfZeroes = 2;
isNeg = false;
if (M < 0)
{
M = Math.abs(M);
isNeg = true;
}
Mo = Math.round(M) + "";
while(Mo.length < amtOfZeroes)
{
Mo = "0" + Mo;
}
if (isNeg)
Mo = "-" + Mo;
if (H < 0)
{
H = Math.abs(H);
isNeg = true;
}
Ho = Math.round(H) + "";
while(Ho.length < amtOfZeroes)
{
Ho = "0" + Ho;
}
if (isNeg)
Ho = "-" + Ho;
if (Mi < 0)
{
Mi = Math.abs(Mi);
isNeg = true;
}
Min = Math.round(Mi) + "";
while(Min.length < amtOfZeroes)
{
Min = "0" + Min;
}
if (isNeg)
Min = "-" + Min;
T = Ho + ":" + (Min)
Mo + "/" + D.getDate() + "/" + D.getFullYear() + " " + T + " " + N
<p id="DateTimeBox">点击按钮显示日期和时间 <按钮onclick = " ShowDate ();">显示日期</button> . < >脚本 函数ShowDate() { . getelementbyid(“DateTimeBox”)。innerHTML = Date(); ｝ > < /脚本
试试这个:
var today = new Date();
var date = today.getFullYear()+'-'+(today.getMonth()+1)+'-'+today.getDate();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date+' '+time;
输出:
2022-3-3 15:52:45
只使用:
var d = new Date();
document.write(d.toLocaleString());
document.write("<br>");
function getTimeStamp() {
var now = new Date();
return ((now.getMonth() + 1) + '/' + (now.getDate()) + '/' + now.getFullYear() + " " + now.getHours() + ':'
+ ((now.getMinutes() < 10) ? ("0" + now.getMinutes()) : (now.getMinutes())) + ':' + ((now.getSeconds() < 10) ? ("0" + now
.getSeconds()) : (now.getSeconds())));
}
