我有一个脚本，打印当前的日期和时间在JavaScript，但日期总是错误的。代码如下:
var currentdate = new Date();
var datetime = "Last Sync: " + currentdate.getDay() + "/" + currentdate.getMonth()
+ "/" + currentdate.getFullYear() + " @ "
+ currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":" + currentdate.getSeconds();
它应该打印18/04/2012 15:07:33和打印3/3/2012 15:07:33
当前回答
这应该可以达到目的:
function dateToString(date) {
var month = date.getMonth() + 1;
var day = date.getDate();
var dateOfString = (("" + day).length < 2 ? "0" : "") + day + "/";
dateOfString += (("" + month).length < 2 ? "0" : "") + month + "/";
dateOfString += date.getFullYear();
return dateOfString;
}
var currentdate = new Date();
var datetime = "Last Sync: ";
datetime += dateToString(currentdate );
datetime += + currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":"
+ currentdate.getSeconds();
其他回答
我们可以用: new Date().toLocaleDateString()获取当前日期和 new Date().toLocaleTimeString()获取当前时间
Ex:
const date = new Date().toLocaleDateString();
const time = new Date().toLocaleTimeString();
只使用:
var d = new Date();
document.write(d.toLocaleString());
document.write("<br>");
这应该可以达到目的:
function dateToString(date) {
var month = date.getMonth() + 1;
var day = date.getDate();
var dateOfString = (("" + day).length < 2 ? "0" : "") + day + "/";
dateOfString += (("" + month).length < 2 ? "0" : "") + month + "/";
dateOfString += date.getFullYear();
return dateOfString;
}
var currentdate = new Date();
var datetime = "Last Sync: ";
datetime += dateToString(currentdate );
datetime += + currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":"
+ currentdate.getSeconds();
const date = new Date()
console.log(date.toLocaleTimeString("en-us", {timeStyle: "medium"})) // Only Time
console.log(date.toLocaleString()) // For both Date and Time
为文档
var currentdate = new Date();
var datetime = "Last Sync: " + currentdate.getDate() + "/"+(currentdate.getMonth()+1)
+ "/" + currentdate.getFullYear() + " @ "
+ currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":" + currentdate.getSeconds();
将. getday()方法更改为. getdate()，并将1添加到month，因为它从0开始计算月份。
