答案可以从很多方面给出。你也可以使用ValueAnimator的ofArgb(startColor,endColor)。

火灾> 21:

int cyanColorBg = ContextCompat.getColor(this,R.color.cyan_bg);
int purpleColorBg = ContextCompat.getColor(this,R.color.purple_bg);

ValueAnimator valueAnimator = ValueAnimator.ofArgb(cyanColorBg,purpleColorBg);
        valueAnimator.setDuration(500);
        valueAnimator.setInterpolator(new LinearInterpolator());
        valueAnimator.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
              @Override
              public void onAnimationUpdate(ValueAnimator valueAnimator) {
                   relativeLayout.setBackgroundColor((Integer)valueAnimator.getAnimatedValue());
              }
        });
        valueAnimator.start();

在Kotlin中使用以下函数:

private fun animateColorValue(view: View) {
    val colorAnimation =
        ValueAnimator.ofObject(ArgbEvaluator(), Color.GRAY, Color.CYAN)
    colorAnimation.duration = 500L
    colorAnimation.addUpdateListener { animator -> view.setBackgroundColor(animator.animatedValue as Int) }
    colorAnimation.start()
}

传递任何你想改变颜色的视图。

实现这一点的另一种简单方法是使用AlphaAnimation执行渐隐。

将视图设置为ViewGroup 在索引0处添加一个子视图，使用match_parent布局维度 给你的孩子与容器相同的背景 更改容器的背景为目标颜色 使用AlphaAnimation淡出子动画。 当动画完成时删除子动画(使用AnimationListener)

罗曼米诺克回答在kotlin和作为扩展函数

fun View.colorTransition(@ColorRes startColor: Int, @ColorRes endColor: Int, duration: Long = 250L){
    val colorFrom = ContextCompat.getColor(context, startColor)
    val colorTo =  ContextCompat.getColor(context, endColor)
    val colorAnimation: ValueAnimator = ValueAnimator.ofObject(ArgbEvaluator(), colorFrom, colorTo)
    colorAnimation.duration = duration

    colorAnimation.addUpdateListener {
        if (it.animatedValue is Int) {
            val color=it.animatedValue as Int
            setBackgroundColor(color)
        }
    }
    colorAnimation.start()
}

如果你想改变当前的背景色到新的颜色，那么你可以使用这个

fun View.colorTransition(@ColorRes endColor: Int, duration: Long = 250L){
    var colorFrom = Color.TRANSPARENT
    if (background is ColorDrawable)
        colorFrom = (background as ColorDrawable).color

    val colorTo =  ContextCompat.getcolor(context, endColor)
    val colorAnimation: ValueAnimator = ValueAnimator.ofObject(ArgbEvaluator(), colorFrom, colorTo)
    colorAnimation.duration = duration

    colorAnimation.addUpdateListener {
        if (it.animatedValue is Int) {
            val color=it.animatedValue as Int
            setBackgroundColor(color)
        }
    }
    colorAnimation.start()
}

使用

myView.colorTransition(R.color.bg_color)

基于ademar111190的答案，我创建了这个方法，它将在任意两种颜色之间脉冲视图的背景颜色:

private void animateBackground(View view, int colorFrom, int colorTo, int duration) {


    ObjectAnimator objectAnimator = ObjectAnimator.ofObject(view, "backgroundColor", new ArgbEvaluator(), colorFrom, colorTo);
    objectAnimator.setDuration(duration);
    //objectAnimator.setRepeatCount(Animation.INFINITE);
    objectAnimator.addListener(new Animator.AnimatorListener() {
        @Override
        public void onAnimationStart(Animator animation) {

        }

        @Override
        public void onAnimationEnd(Animator animation) {
            // Call this method again, but with the two colors switched around.
            animateBackground(view, colorTo, colorFrom, duration);
        }

        @Override
        public void onAnimationCancel(Animator animation) {

        }

        @Override
        public void onAnimationRepeat(Animator animation) {

        }
    });
    objectAnimator.start();
}

如果你想要这样的彩色动画，

这段代码将帮助你:

ValueAnimator anim = ValueAnimator.ofFloat(0, 1);   
anim.setDuration(2000);

float[] hsv;
int runColor;
int hue = 0;
hsv = new float[3]; // Transition color
hsv[1] = 1;
hsv[2] = 1;
anim.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {

    @Override
    public void onAnimationUpdate(ValueAnimator animation) {

        hsv[0] = 360 * animation.getAnimatedFraction();

        runColor = Color.HSVToColor(hsv);
        yourView.setBackgroundColor(runColor);
    }
});

anim.setRepeatCount(Animation.INFINITE);

anim.start();