这里是Jakob Egger方法的Swift版本:

import UIKit

private weak var currentFirstResponder: UIResponder?

extension UIResponder {

    static func firstResponder() -> UIResponder? {
        currentFirstResponder = nil
        UIApplication.sharedApplication().sendAction(#selector(self.findFirstResponder(_:)), to: nil, from: nil, forEvent: nil)
        return currentFirstResponder
    }

    func findFirstResponder(sender: AnyObject) {
        currentFirstResponder = self
    }

}

遍历可能是第一响应器的视图，并使用- (BOOL)isFirstResponder来确定它们当前是否是。

这是一个类别，允许您通过调用[UIResponder currentFirstResponder]快速找到第一个响应器。只需添加以下两个文件到您的项目:

UIResponder + FirstResponder.h:

#import <Cocoa/Cocoa.h>
@interface UIResponder (FirstResponder)
    +(id)currentFirstResponder;
@end

UIResponder + FirstResponder.m:

#import "UIResponder+FirstResponder.h"
static __weak id currentFirstResponder;
@implementation UIResponder (FirstResponder)
    +(id)currentFirstResponder {
         currentFirstResponder = nil;
         [[UIApplication sharedApplication] sendAction:@selector(findFirstResponder:) to:nil from:nil forEvent:nil];
         return currentFirstResponder;
    }
    -(void)findFirstResponder:(id)sender {
        currentFirstResponder = self;
    }
@end

这里的技巧是将一个动作发送给nil将它发送给第一个响应者。

(我最初在这里发表了这个答案:https://stackoverflow.com/a/14135456/322427)

我想和你们分享我的实现，在UIView的任何地方找到第一个响应者。我希望这对我的英语有所帮助，对不起。谢谢

+ (UIView *) findFirstResponder:(UIView *) _view {

    UIView *retorno;

    for (id subView in _view.subviews) {

        if ([subView isFirstResponder])
        return subView;

        if ([subView isKindOfClass:[UIView class]]) {
            UIView *v = subView;

            if ([v.subviews count] > 0) {
                retorno = [self findFirstResponder:v];
                if ([retorno isFirstResponder]) {
                    return retorno;
                }
            }
        }
    }

    return retorno;
}

下面是一个基于Jakob Egger最优秀的答案在Swift中实现的扩展:

import UIKit

extension UIResponder {
    // Swift 1.2 finally supports static vars!. If you use 1.1 see: 
    // http://stackoverflow.com/a/24924535/385979
    private weak static var _currentFirstResponder: UIResponder? = nil
    
    public class func currentFirstResponder() -> UIResponder? {
        UIResponder._currentFirstResponder = nil
        UIApplication.sharedApplication().sendAction("findFirstResponder:", to: nil, from: nil, forEvent: nil)
        return UIResponder._currentFirstResponder
    }
    
    internal func findFirstResponder(sender: AnyObject) {
        UIResponder._currentFirstResponder = self
    }
}

斯威夫特4

import UIKit    

extension UIResponder {
    private weak static var _currentFirstResponder: UIResponder? = nil
    
    public static var current: UIResponder? {
        UIResponder._currentFirstResponder = nil
        UIApplication.shared.sendAction(#selector(findFirstResponder(sender:)), to: nil, from: nil, for: nil)
        return UIResponder._currentFirstResponder
    }
    
    @objc internal func findFirstResponder(sender: AnyObject) {
        UIResponder._currentFirstResponder = self
    }
}

使用Swift和一个特定的UIView对象，这可能会有所帮助:

func findFirstResponder(inView view: UIView) -> UIView? {
    for subView in view.subviews as! [UIView] {
        if subView.isFirstResponder() {
            return subView
        }
        
        if let recursiveSubView = self.findFirstResponder(inView: subView) {
            return recursiveSubView
        }
    }
    
    return nil
}

只需要把它放在你的UIViewController中，然后像这样使用它:

let firstResponder = self.findFirstResponder(inView: self.view)

请注意，结果是一个可选值，所以如果在给定的视图子视图层次结构中没有找到firstResponder，它将为nil。