这里有一种方法:

var date = Date.parse('Sun May 11,2014');

function format(date) {
  date = new Date(date);

  var day = ('0' + date.getDate()).slice(-2);
  var month = ('0' + (date.getMonth() + 1)).slice(-2);
  var year = date.getFullYear();

  return year + '-' + month + '-' + day;
}

console.log(format(date));

你可以:

函数formatDate(日期){ var d = new Date(日期)， 月= " + (d.getMonth() + 1) "， day = " + d.getDate()， year = d.g getfullyear (); 如果(月。长度< 2) 月= '0' +月; 如果一天。长度< 2) Day = '0' + Day; 返回[年，月，日].join('-'); ｝ console.log(formatDate('Sun May 11,2014'));

使用的例子:

console.log(formatDate('Sun May 11,2014'));

输出:

2014-05-11

JSFiddle的演示:http://jsfiddle.net/abdulrauf6182012/2Frm3/

函数 myYmd（D）{ var pad = function（num） { 变量 s = '0' + 数字; 返回 s.substr（s.length - 2）; } var Result = D.getFullYear（） + '-' + pad（（D.getMonth（） + 1）） + '-' + pad（D.getDate（））; 返回结果; } var datemilli = new Date（'Sun May 11，2014'）; document.write（myYmd（datemilli））;

将日期转换为yyyy-mm-dd格式的最简单方法是这样做:

var date = new Date("Sun May 11,2014");
var dateString = new Date(date.getTime() - (date.getTimezoneOffset() * 60000 ))
                    .toISOString()
                    .split("T")[0];

工作原理:

new Date("Sun May 11,2014") converts the string "Sun May 11,2014" to a date object that represents the time Sun May 11 2014 00:00:00 in a timezone based on current locale (host system settings) new Date(date.getTime() - (date.getTimezoneOffset() * 60000 )) converts your date to a date object that corresponds with the time Sun May 11 2014 00:00:00 in UTC (standard time) by subtracting the time zone offset .toISOString() converts the date object to an ISO 8601 string 2014-05-11T00:00:00.000Z .split("T") splits the string to array ["2014-05-11", "00:00:00.000Z"] [0] takes the first element of that array

Demo

var date =新日期(“太阳5月11日”); var dateString =新日期(日期。 toISOString()。 斯普利特(“T”)[0]; 游戏机。log (dateString);

注意:

The first part of the code (new Date(...)) may need to be tweaked a bit if your input format is different from that of the OP. As mikeypie pointed out in the comments, if the date string is already in the expected output format and the local timezone is west of UTC, then new Date('2022-05-18') results in 2022-05-17. And a user's locale (eg. MM/DD/YYYY vs DD-MM-YYYY) may also impact how a date is parsed by new Date(...). So do some proper testing if you want to use this code for different input formats.

以下是一些答案的组合:

var d = new Date(date);
date = [
  d.getFullYear(),
  ('0' + (d.getMonth() + 1)).slice(-2),
  ('0' + d.getDate()).slice(-2)
].join('-');

const today = new Date(); // or whatever const yearFirstFormater = (date): string => { const modifiedDate = new Date(date).toISOString().slice(0, 10); return `${modifiedDate.split('-')[0]}/${modifiedDate.split('-')[1]}/${modifiedDate.split('-')[2]}`; } const monthFirstFormater = (date): string => { const modifiedDate = new Date(date).toISOString().slice(0, 10); return `${modifiedDate.split('-')[1]}/${modifiedDate.split('-')[2]}/${modifiedDate.split('-')[0]}`; } const dayFirstFormater = (date): string => { const modifiedDate = new Date(date).toISOString().slice(0, 10); return `${modifiedDate.split('-')[2]}/${modifiedDate.split('-')[1]}/${modifiedDate.split('-')[0]}`; } console.log(yearFirstFormater(today)); console.log(monthFirstFormater(today)); console.log(dayFirstFormater(today));