将日期转换为yyyy-mm-dd格式的最简单方法是这样做:

var date = new Date("Sun May 11,2014");
var dateString = new Date(date.getTime() - (date.getTimezoneOffset() * 60000 ))
                    .toISOString()
                    .split("T")[0];

工作原理:

new Date("Sun May 11,2014") converts the string "Sun May 11,2014" to a date object that represents the time Sun May 11 2014 00:00:00 in a timezone based on current locale (host system settings) new Date(date.getTime() - (date.getTimezoneOffset() * 60000 )) converts your date to a date object that corresponds with the time Sun May 11 2014 00:00:00 in UTC (standard time) by subtracting the time zone offset .toISOString() converts the date object to an ISO 8601 string 2014-05-11T00:00:00.000Z .split("T") splits the string to array ["2014-05-11", "00:00:00.000Z"] [0] takes the first element of that array

Demo

var date =新日期(“太阳5月11日”); var dateString =新日期(日期。 toISOString()。 斯普利特(“T”)[0]; 游戏机。log (dateString);

注意:

The first part of the code (new Date(...)) may need to be tweaked a bit if your input format is different from that of the OP. As mikeypie pointed out in the comments, if the date string is already in the expected output format and the local timezone is west of UTC, then new Date('2022-05-18') results in 2022-05-17. And a user's locale (eg. MM/DD/YYYY vs DD-MM-YYYY) may also impact how a date is parsed by new Date(...). So do some proper testing if you want to use this code for different input formats.

之前的一些答案是可以的，但是不是很灵活。我想要一些能够真正处理更多边缘情况的东西，所以我采用了@orangleliu的答案并扩展了它。https://jsfiddle.net/8904cmLd/1/

function DateToString(inDate, formatString) {
    // Written by m1m1k 2018-04-05

    // Validate that we're working with a date
    if(!isValidDate(inDate))
    {
        inDate = new Date(inDate);
    }

    // See the jsFiddle for extra code to be able to use DateToString('Sun May 11,2014', 'USA');
    //formatString = CountryCodeToDateFormat(formatString);

    var dateObject = {
        M: inDate.getMonth() + 1,
        d: inDate.getDate(),
        D: inDate.getDate(),
        h: inDate.getHours(),
        m: inDate.getMinutes(),
        s: inDate.getSeconds(),
        y: inDate.getFullYear(),
        Y: inDate.getFullYear()
    };

    // Build Regex Dynamically based on the list above.
    // It should end up with something like this: "/([Yy]+|M+|[Dd]+|h+|m+|s+)/g"
    var dateMatchRegex = joinObj(dateObject, "+|") + "+";
    var regEx = new RegExp(dateMatchRegex,"g");
    formatString = formatString.replace(regEx, function(formatToken) {
        var datePartValue = dateObject[formatToken.slice(-1)];
        var tokenLength = formatToken.length;

        // A conflict exists between specifying 'd' for no zero pad -> expand
        // to '10' and specifying yy for just two year digits '01' instead
        // of '2001'.  One expands, the other contracts.
        //
        // So Constrict Years but Expand All Else
        if (formatToken.indexOf('y') < 0 && formatToken.indexOf('Y') < 0)
        {
            // Expand single digit format token 'd' to
            // multi digit value '10' when needed
            var tokenLength = Math.max(formatToken.length, datePartValue.toString().length);
        }
        var zeroPad = (datePartValue.toString().length < formatToken.length ? "0".repeat(tokenLength) : "");
        return (zeroPad + datePartValue).slice(-tokenLength);
    });

    return formatString;
}

使用示例:

DateToString('Sun May 11,2014', 'MM/DD/yy');
DateToString('Sun May 11,2014', 'yyyy.MM.dd');
DateToString(new Date('Sun Dec 11,2014'),'yy-M-d');

你可以:

函数formatDate(日期){ var d = new Date(日期)， 月= " + (d.getMonth() + 1) "， day = " + d.getDate()， year = d.g getfullyear (); 如果(月。长度< 2) 月= '0' +月; 如果一天。长度< 2) Day = '0' + Day; 返回[年，月，日].join('-'); ｝ console.log(formatDate('Sun May 11,2014'));

使用的例子:

console.log(formatDate('Sun May 11,2014'));

输出:

2014-05-11

JSFiddle的演示:http://jsfiddle.net/abdulrauf6182012/2Frm3/

这很容易由我的date-shortcode包完成:

const dateShortcode = require('date-shortcode')
dateShortcode.parse('{YYYY-MM-DD}', 'Sun May 11,2014')
//=> '2014-05-11'

formatDate(date) {
  const d = new Date(date)
  const ye = new Intl.DateTimeFormat('en', { year: 'numeric' }).format(d);
  const mo = new Intl.DateTimeFormat('en', { month: 'short' }).format(d);
  const da = new Intl.DateTimeFormat('en', { day: '2-digit' }).format(d);
  return `${da}-${mo}-${ye}`;
}

console.log("Formatated Date : ", formatDate("09/25/2020") )
// Output :: Formatated Date : 25-Sep-2020

这为我工作，以所需的格式(YYYYMMDD HH:MM:SS)获取当前日期:

var d = new Date();

var date1 = d.getFullYear() + '' +
            ((d.getMonth()+1) < 10 ? "0" + (d.getMonth() + 1) : (d.getMonth() + 1)) +
            '' +
            (d.getDate() < 10 ? "0" + d.getDate() : d.getDate());

var time1 = (d.getHours() < 10 ? "0" + d.getHours() : d.getHours()) +
            ':' +
            (d.getMinutes() < 10 ? "0" + d.getMinutes() : d.getMinutes()) +
            ':' +
            (d.getSeconds() < 10 ? "0" + d.getSeconds() : d.getSeconds());

print(date1+' '+time1);