如果你想要恢复到上一次提交并删除日志历史记录

使用下面的命令，让我们假设你想要去到以前的提交，它有commititid SHA - 71e2e57458bde883a37b332035f784c6653ec509，你可以指向这个提交，它将不会显示任何日志消息在这个提交之后，所有的历史将被擦除。

git push origin +71e2e57458bde883a37b332035f784c6653ec509^:master

你基本上有两个选择:

You merge. That is actually quite simple, and a perfectly local operation: git checkout b1 git merge master # repeat for b2 and b3 This leaves the history exactly as it happened: You forked from master, you made changes to all branches, and finally you incorporated the changes from master into all three branches. git can handle this situation really well, it is designed for merges happening in all directions, at the same time. You can trust it be able to get all threads together correctly. It simply does not care whether branch b1 merges master, or master merges b1, the merge commit looks all the same to git. The only difference is, which branch ends up pointing to this merge commit. You rebase. People with an SVN, or similar background find this more intuitive. The commands are analogue to the merge case: git checkout b1 git rebase master # repeat for b2 and b3 People like this approach because it retains a linear history in all branches. However, this linear history is a lie, and you should be aware that it is. Consider this commit graph: A --- B --- C --- D <-- master \ \-- E --- F --- G <-- b1 The merge results in the true history: A --- B --- C --- D <-- master \ \ \-- E --- F --- G +-- H <-- b1 The rebase, however, gives you this history: A --- B --- C --- D <-- master \ \-- E' --- F' --- G' <-- b1 The point is, that the commits E', F', and G' never truly existed, and have likely never been tested. They may not even compile. It is actually quite easy to create nonsensical commits via a rebase, especially when the changes in master are important to the development in b1. The consequence of this may be, that you can't distinguish which of the three commits E, F, and G actually introduced a regression, diminishing the value of git bisect. I am not saying that you shouldn't use git rebase. It has its uses. But whenever you do use it, you need to be aware of the fact that you are lying about history. And you should at least compile test the new commits.

对于这个问题有两种选择。

1） Git 变基

2）去合并

只有与上述两者不同的合并情况下，将有额外的历史提交

1) git结帐分支(b1,b2,b3)

2) git rebase origin/master(如果冲突可以通过git rebase -continue在本地解决)

3）去推

或者，git合并选项是类似的方式

1) git checkout“your_branch”(b1,b2,b3)

2）转到合并母版

3）去推

如果你想要恢复到上一次提交并删除日志历史记录

使用下面的命令，让我们假设你想要去到以前的提交，它有commititid SHA - 71e2e57458bde883a37b332035f784c6653ec509，你可以指向这个提交，它将不会显示任何日志消息在这个提交之后，所有的历史将被擦除。

git push origin +71e2e57458bde883a37b332035f784c6653ec509^:master

@cmaster给出了最好的详细回答。简而言之:

git checkout master #
git pull # update local master from remote master
git checkout <your_branch>
git merge master # solve merge conflicts if you have`

您不应该重写分支历史记录，而应该保持它们的实际状态以供将来引用。当合并到master时，它会创建一个额外的提交，但这很便宜。提交不需要成本。

你有两个选择:

第一个是合并，但是这为合并创建了一个额外的提交。

检查每个分支:

git checkout b1

然后合并:

git merge origin/master

然后推:

git push origin b1

或者，你可以做一个rebase:

git fetch
git rebase origin/master