我有一个有很多对象的工作空间，我想删除所有的，但只有一个。理想情况下，我希望避免键入rm(obj。1、obj.2……obj.n)。是否有可能指示删除除这些对象之外的所有对象?
当前回答
从函数内部，rm .GlobalEnv中除函数外的所有对象
initialize <- function(country.name) {
if (length(setdiff(ls(pos = .GlobalEnv), "initialize")) > 0) {
rm(list=setdiff(ls(pos = .GlobalEnv), "initialize"), pos = .GlobalEnv)
}
}
其他回答
这个怎么样?
# Removes all objects except the specified & the function itself.
rme <- function(except=NULL){
except = ifelse(is.character(except), except, deparse(substitute(except)))
rm(list=setdiff(ls(envir=.GlobalEnv), c(except,"rme")), envir=.GlobalEnv)
}
从函数内部，rm .GlobalEnv中除函数外的所有对象
initialize <- function(country.name) {
if (length(setdiff(ls(pos = .GlobalEnv), "initialize")) > 0) {
rm(list=setdiff(ls(pos = .GlobalEnv), "initialize"), pos = .GlobalEnv)
}
}
将v替换为要保留的对象的名称
rm(list=(ls()[ls()!="v"]))
hat-tip: http://r.789695.n4.nabble.com/Removing-objects-and-clearing-memory-tp3445763p3445865.html
require(gdata)
keep(object_1,...,object_n,sure=TRUE)
ls()
使用gdata包中的keep函数非常方便。
> ls()
[1] "a" "b" "c"
library(gdata)
> keep(a) #shows you which variables will be removed
[1] "b" "c"
> keep(a, sure = TRUE) # setting sure to TRUE removes variables b and c
> ls()
[1] "a"
