我有一个有很多对象的工作空间,我想删除所有的,但只有一个。理想情况下,我希望避免键入rm(obj。1、obj.2……obj.n)。是否有可能指示删除除这些对象之外的所有对象?
当前回答
使用gdata包中的keep函数非常方便。
> ls()
[1] "a" "b" "c"
library(gdata)
> keep(a) #shows you which variables will be removed
[1] "b" "c"
> keep(a, sure = TRUE) # setting sure to TRUE removes variables b and c
> ls()
[1] "a"
其他回答
下面的操作将从控制台删除所有对象
rm(list = ls())
这利用了ls()的模式选项,在这种情况下,你有很多具有相同模式的对象,而你不想保留:
> foo1 <- "junk"; foo2 <- "rubbish"; foo3 <- "trash"; x <- "gold"
> ls()
[1] "foo1" "foo2" "foo3" "x"
> # Let's check first what we want to remove
> ls(pattern = "foo")
[1] "foo1" "foo2" "foo3"
> rm(list = ls(pattern = "foo"))
> ls()
[1] "x"
从函数内部,rm .GlobalEnv中除函数外的所有对象
initialize <- function(country.name) {
if (length(setdiff(ls(pos = .GlobalEnv), "initialize")) > 0) {
rm(list=setdiff(ls(pos = .GlobalEnv), "initialize"), pos = .GlobalEnv)
}
}
require(gdata)
keep(object_1,...,object_n,sure=TRUE)
ls()
要保存对象列表,可以使用:
rm(list=setdiff(ls(), c("df1", "df2")))