我如何写多行文件称为myconfig.conf使用BASH?
#!/bin/bash
kernel="2.6.39";
distro="xyz";
echo <<< EOL
line 1, ${kernel}
line 2,
line 3, ${distro}
line 4
line ...
EOL >> /etc/myconfig.conf;
cat /etc/myconfig.conf;
我如何写多行文件称为myconfig.conf使用BASH?
#!/bin/bash
kernel="2.6.39";
distro="xyz";
echo <<< EOL
line 1, ${kernel}
line 2,
line 3, ${distro}
line 4
line ...
EOL >> /etc/myconfig.conf;
cat /etc/myconfig.conf;
当前回答
另一种更简单的方法,但绝对适用于少量的行数
touch myfile.txt
echo "line1">>myfile.txt
echo "line2">>myfile.txt
echo "line3">>myfile.txt
echo "line4">>myfile.txt
其他回答
如果不希望替换变量,则需要用单引号将EOL括起来。
cat >/tmp/myconfig.conf <<'EOL'
line 1, ${kernel}
line 2,
line 3, ${distro}
line 4 line
...
EOL
前一个例子:
$ cat /tmp/myconfig.conf
line 1, ${kernel}
line 2,
line 3, ${distro}
line 4 line
...
#!/bin/bash
kernel="2.6.39";
distro="xyz";
cat > /etc/myconfig.conf << EOL
line 1, ${kernel}
line 2,
line 3, ${distro}
line 4
line ...
EOL
这就是你想要的。
另一种更简单的方法,但绝对适用于少量的行数
touch myfile.txt
echo "line1">>myfile.txt
echo "line2">>myfile.txt
echo "line3">>myfile.txt
echo "line4">>myfile.txt
语法(<<<)和使用的命令(echo)错误。
正确的做法是:
#!/bin/bash
kernel="2.6.39"
distro="xyz"
cat >/etc/myconfig.conf <<EOL
line 1, ${kernel}
line 2,
line 3, ${distro}
line 4 line
...
EOL
cat /etc/myconfig.conf
这个结构被称为Here Document,可以在Bash手册页的man -pager='less -p "\s*Here Documents"' Bash下找到。
这里的解决方案当然是最常见的方法。其他常见的解决方案有:
echo 'line 1, '"${kernel}"'
line 2,
line 3, '"${distro}"'
line 4' > /etc/myconfig.conf
and
exec 3>&1 # Save current stdout
exec > /etc/myconfig.conf
echo line 1, ${kernel}
echo line 2,
echo line 3, ${distro}
...
exec 1>&3 # Restore stdout
and
printf "%s\n" "line1, ${kernel}" "line2," "line3, $distro" ...