aws s3 cp s3://source_folder/ s3://destination_folder/ --recursive
aws s3 rm s3://source_folder --recursive

文件和文件夹实际上是S3中的对象。你应该使用PUT OBJECT COPY来重命名它们。参见http://docs.aws.amazon.com/AmazonS3/latest/API/RESTObjectCOPY.html

s3中的文件夹结构有很多“问题”，似乎存储是扁平的。

我有一个Django项目，我需要重命名文件夹，但仍然保持目录结构不变，这意味着空文件夹也需要复制并存储在重命名的目录中。

aws cli很棒，但cp或sync或mv都没有将空文件夹(即以'/'结尾的文件)复制到新的文件夹位置，所以我使用boto3和aws cli的混合来完成任务。

或多或少我找到重命名目录中的所有文件夹，然后使用boto3将它们放在新位置，然后我用aws cli对数据进行cp，最后将其删除。

import threading

import os
from django.conf import settings
from django.contrib import messages
from django.core.files.storage import default_storage
from django.shortcuts import redirect
from django.urls import reverse

def rename_folder(request, client_url):
    """
    :param request:
    :param client_url:
    :return:
    """
    current_property = request.session.get('property')
    if request.POST:
        # name the change
        new_name = request.POST['name']
        # old full path with www.[].com?
        old_path = request.POST['old_path']
        # remove the query string
        old_path = ''.join(old_path.split('?')[0])
        # remove the .com prefix item so we have the path in the storage
        old_path = ''.join(old_path.split('.com/')[-1])
        # remove empty values, this will happen at end due to these being folders
        old_path_list = [x for x in old_path.split('/') if x != '']

        # remove the last folder element with split()
        base_path = '/'.join(old_path_list[:-1])
        # # now build the new path
        new_path = base_path + f'/{new_name}/'
        # remove empty variables
        # print(old_path_list[:-1], old_path.split('/'), old_path, base_path, new_path)
        endpoint = settings.AWS_S3_ENDPOINT_URL
        # # recursively add the files
        copy_command = f"aws s3 --endpoint={endpoint} cp s3://{old_path} s3://{new_path} --recursive"
        remove_command = f"aws s3 --endpoint={endpoint} rm s3://{old_path} --recursive"
        
        # get_creds() is nothing special it simply returns the elements needed via boto3
        client, resource, bucket, resource_bucket = get_creds()
        path_viewing = f'{"/".join(old_path.split("/")[1:])}'
        directory_content = default_storage.listdir(path_viewing)

        # loop over folders and add them by default, aws cli does not copy empty ones
        # so this is used to accommodate
        folders, files = directory_content
        for folder in folders:
            new_key = new_path+folder+'/'
            # we must remove bucket name for this to work
            new_key = new_key.split(f"{bucket}/")[-1]
            # push this to new thread
            threading.Thread(target=put_object, args=(client, bucket, new_key,)).start()
            print(f'{new_key} added')

        # # run command, which will copy all data
        os.system(copy_command)
        print('Copy Done...')
        os.system(remove_command)
        print('Remove Done...')

        # print(bucket)
        print(f'Folder renamed.')
        messages.success(request, f'Folder Renamed to: {new_name}')

    return redirect(request.META.get('HTTP_REFERER', f"{reverse('home', args=[client_url])}"))

S3中没有重命名文件的直接方法。你所要做的就是复制现有文件的新名称(只要设置目标键)，然后删除旧的。

如果您想重命名s3文件夹中的许多文件，可以运行以下脚本。

    FILES=$(aws s3api list-objects --bucket your_bucket --prefix 'your_path' --delimiter '/'  | jq -r '.Contents[] | select(.Size > 0) | .Key' | sed '<your_rename_here>')
     for i in $FILES
     do
      aws s3 mv s3://<your_bucket>/${i}.gz s3://<your_bucket>/${i}
     done   

我所做的是创建一个新文件夹，并将旧的files对象移动到新文件夹。