试试这个:

public void checkForEncode(String string) {
    String pattern = "^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{4}|[A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)$";
    Pattern r = Pattern.compile(pattern);
    Matcher m = r.matcher(string);
    if (m.find()) {
        System.out.println("true");
    } else {
        System.out.println("false");
    }
}

您可以使用以下正则表达式来检查字符串是否构成有效的base64编码:

^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)?$

在base64编码中，字符集为[A-Z, A-Z, 0-9和+ /]。如果其余长度小于4，则字符串用'='字符填充。

^([A-Za-z0-9+/]{4})*表示字符串以0个或多个base64组开头。

([A-Za-z0-9 + /] {4} | [A-Za-z0-9 + /] {3} = | [A-Za-z0-9 + /]{2} = =)意味着美元的字符串以三种形式之一:A-Za-z0-9 + / {4}, {3} = [A-Za-z0-9 + /]或[A-Za-z0-9 + /]{2} = =。

PHP5试试这样做

//where $json is some data that can be base64 encoded
$json=some_data;

//this will check whether data is base64 encoded or not
if (base64_decode($json, true) == true)
{          
   echo "base64 encoded";          
}
else 
{
   echo "not base64 encoded"; 
}

在PHP7中使用这个

 //$string parameter can be base64 encoded or not

function is_base64_encoded($string){
 //this will check if $string is base64 encoded and return true, if it is.
 if (base64_decode($string, true) !== false){          
   return true;        
 }else{
   return false;
 }
}

如果你正在使用Java，你实际上可以使用common -codec库

import org.apache.commons.codec.binary.Base64;

String stringToBeChecked = "...";
boolean isBase64 = Base64.isArrayByteBase64(stringToBeChecked.getBytes());

[更新1]弃用通知 而不是使用

Base64.isBase64(价值);

   /**
     * Tests a given byte array to see if it contains only valid characters within the Base64 alphabet. Currently the
     * method treats whitespace as valid.
     *
     * @param arrayOctet
     *            byte array to test
     * @return {@code true} if all bytes are valid characters in the Base64 alphabet or if the byte array is empty;
     *         {@code false}, otherwise
     * @deprecated 1.5 Use {@link #isBase64(byte[])}, will be removed in 2.0.
     */
    @Deprecated
    public static boolean isArrayByteBase64(final byte[] arrayOctet) {
        return isBase64(arrayOctet);
    }

我试着用这个，是的，这个有用

^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)?$

但我添加了一个条件，检查至少字符的结尾是=

string.lastIndexOf("=") >= 0

对于Flutter，我测试了上面的几个注释，并将其转换为dart函数，如下所示

  static bool isBase64(dynamic value) {

    if (value.runtimeType == String){
      
      final RegExp rx = RegExp(r'^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)?$',
          multiLine: true,
          unicode: true,
      );

      final bool isBase64Valid = rx.hasMatch(value);

      if (isBase64Valid == true) {return true;}
      else {return false;}

    }

    else {return false;}

  }