c# 这表现得很好:

static readonly Regex _base64RegexPattern = new Regex(BASE64_REGEX_STRING, RegexOptions.Compiled);

private const String BASE64_REGEX_STRING = @"^[a-zA-Z0-9\+/]*={0,3}$";

private static bool IsBase64(this String base64String)
{
    var rs = (!string.IsNullOrEmpty(base64String) && !string.IsNullOrWhiteSpace(base64String) && base64String.Length != 0 && base64String.Length % 4 == 0 && !base64String.Contains(" ") && !base64String.Contains("\t") && !base64String.Contains("\r") && !base64String.Contains("\n")) && (base64String.Length % 4 == 0 && _base64RegexPattern.Match(base64String, 0).Success);
    return rs;
}

这在Python中是有效的:

import base64

def IsBase64(str):
    try:
        base64.b64decode(str)
        return True
    except Exception as e:
        return False

if IsBase64("ABC"):
    print("ABC is Base64-encoded and its result after decoding is: " + str(base64.b64decode("ABC")).replace("b'", "").replace("'", ""))
else:
    print("ABC is NOT Base64-encoded.")

if IsBase64("QUJD"):
    print("QUJD is Base64-encoded and its result after decoding is: " + str(base64.b64decode("QUJD")).replace("b'", "").replace("'", ""))
else:
    print("QUJD is NOT Base64-encoded.")

IsBase64("string here")如果这里的字符串是base64编码的则返回true，如果这里的字符串不是base64编码的则返回false。

Function Check_If_Base64(ByVal msgFile As String) As Boolean
Dim I As Long
Dim Buffer As String
Dim Car As String

Check_If_Base64 = True

Buffer = Leggi_File(msgFile)
Buffer = Replace(Buffer, vbCrLf, "")
For I = 1 To Len(Buffer)
    Car = Mid(Buffer, I, 1)
    If (Car < "A" Or Car > "Z") _
    And (Car < "a" Or Car > "z") _
    And (Car < "0" Or Car > "9") _
    And (Car <> "+" And Car <> "/" And Car <> "=") Then
        Check_If_Base64 = False
        Exit For
    End If
Next I
End Function
Function Leggi_File(PathAndFileName As String) As String
Dim FF As Integer
FF = FreeFile()
Open PathAndFileName For Binary As #FF
Leggi_File = Input(LOF(FF), #FF)
Close #FF
End Function

在Java中，以下代码适用于我:

public static boolean isBase64Encoded(String s) {
        String pattern = "^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)?$";
        Pattern r = Pattern.compile(pattern);
        Matcher m = r.matcher(s);
        return m.find();
    }

如果RegEx不起作用，而您知道原始字符串的格式风格，则可以通过对该格式进行RegEx来反转逻辑。

例如，我使用base64编码的xml文件，只检查文件是否包含有效的xml标记。如果没有，我可以假设它是base64解码的。这不是很动态，但对于我的小应用程序来说很好。

检查字符串的长度是否为4的倍数。然后使用这个正则表达式来确保字符串中的所有字符都是base64字符。

\A[a-zA-Z\d\/+]+={，2}\z

如果您使用的库添加换行符作为遵守每行最多76个字符规则的一种方式，请将它们替换为空字符串。